為什么我的while循環不會永遠結束？ C ++

Question

int main ()
{

int wordCode;

const int QUIT_MENU = 9;

菜單

do
{
    cout << "Given the phrase:" << endl;
    cout << "Now is the time for all good men to come to the aid of their ___.\n" << endl;
    cout << "Input a 1 if you want the sentence to be finished with party." << endl;
    cout << "Input any other number for the word country.\n" << endl;
    cout << "Please input your choice now." << endl;
    cin  >> wordCode;
    cout << endl;
    writeProverb(wordCode);

while (wordCode >= 1 || wordCode <= 2)
{
        cout << "You have not entered a valid selection." << endl;
        cout << "Please eneter a 1 or a 2." << endl;

    }

    if (wordCode != QUIT_MENU)
    {
        switch (wordCode)
        {
            case 1:
                writeProverb(wordCode);
                break;
            case 2:
                writeProverb(wordCode);
        }
    }

是否有退出此循環的正確方法？

}while (wordCode != QUIT_MENU);

return 0;
}

void函數開始寫諺語。

void writeProverb (int wordCode)
{
 //Fill in the body of the function to accomplish what is described above

if (wordCode == 1)
{
    cout << "Now is the time for all good men to come to the aid of their party." << endl;
}

if (wordCode == 2)
{
    cout << "Now is the time for all good men to come to aid the aid of their country." << endl;
}

}

“您尚未輸入有效的選擇。” “請將1或2設為Eneter。”

無論選擇什么值，以上文本都會重復。

Answer 1

為什么要這樣

while (wordCode >= 1 || wordCode <= 2)

用戶輸入：

           wordCode >= 1      wordCode <= 2            
1              True                True            -> True  || True -> True
-1             False               True            -> False || True -> True
2              True                True            -> True  || True -> True
3              True                False           -> True  || False -> True
999999         True                False           -> True  || False -> True
-99999         False               True            -> False || True -> True

無論用戶輸入什么數字，條件從字面上都不會變為假。

Answer 2

更改

while (wordCode >= 1 || wordCode <= 2)

至

if (wordCode == 1 || wordCode == 2)

您不希望該部分循環。 外部的do/while處理就好了。 您只需要輸出一次消息。

Answer 3

要添加到馬克·B的答案中，我想您需要while (wordCode == 1 || wordCode == 2)

Answer 4

將“ while（wordCode> = 1 || wordCode <= 2）”更改為“ while（wordCode> = 1 && wordCode <= 2）”。 那應該解決您的循環。