[英]Android Register Form with PHP and MySQL
我將創建一個簡單的注冊表單應用程序,當用戶插入用戶名和密碼時 ,UI中的EditText會在數據庫中顯示其記錄的ID 。
我的應用程序將用戶正確地插入數據庫; 只是我的EditText不顯示id ...
activity_main.xml中
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:tools="http://schemas.android.com/tools"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:background="#00aeef"
android:paddingBottom="@dimen/activity_vertical_margin"
android:paddingLeft="@dimen/activity_horizontal_margin"
android:paddingRight="@dimen/activity_horizontal_margin"
android:paddingTop="@dimen/activity_vertical_margin"
tools:context=".MainActivity" >
<TextView
android:id="@+id/textView3"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_alignParentTop="true"
android:layout_centerHorizontal="true"
android:layout_marginBottom="50dp"
android:layout_marginTop="18dp"
android:text="Register Example"
android:textAppearance="?android:attr/textAppearanceLarge"
android:textColor="#ffffff" />
<TextView
android:id="@+id/textView1"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_alignTop="@+id/textView3"
android:layout_centerHorizontal="true"
android:layout_marginTop="45dp"
android:text="Username:"
android:textAppearance="?android:attr/textAppearanceLarge"
android:textColor="#ffffff" />
<EditText
android:id="@+id/edt_username"
android:layout_width="250dp"
android:layout_height="40dp"
android:layout_below="@+id/textView3"
android:layout_centerHorizontal="true"
android:background="#ffffff"
android:ems="10"
android:padding="5dp" >
<requestFocus />
</EditText>
<Button
android:id="@+id/btn_insert"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:layout_alignLeft="@+id/edt_result"
android:layout_below="@+id/edt_password"
android:layout_marginTop="16dp"
android:background="#ffffff"
android:text="Insert"
android:textColor="#00aeef" />
<TextView
android:id="@+id/textView2"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_alignRight="@+id/textView1"
android:layout_below="@+id/edt_username"
android:text="Password:"
android:textAppearance="?android:attr/textAppearanceLarge"
android:textColor="#ffffff" />
<EditText
android:id="@+id/edt_password"
android:layout_width="250dp"
android:layout_height="40dp"
android:layout_alignLeft="@+id/edt_username"
android:layout_below="@+id/textView2"
android:background="#ffffff"
android:ems="10"
android:padding="5dp" />
<EditText
android:id="@+id/edt_result"
android:layout_width="match_parent"
android:layout_height="40dp"
android:layout_below="@+id/btn_insert"
android:layout_centerHorizontal="true"
android:layout_marginTop="22dp"
android:background="#ffffff"
android:ems="10"
android:padding="5dp" />
</RelativeLayout>
InsertClass.java
package com.example.testphp;
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.io.OutputStreamWriter;
import java.net.URL;
import java.net.URLConnection;
import java.net.URLEncoder;
import android.app.ProgressDialog;
import android.content.Context;
import android.os.AsyncTask;
public class InsertClass extends AsyncTask<String, Void, String>{
private Context context;
private ProgressDialog pDialog;
private EditText edt;
private String json = "";
private JSONObject jObj = null;
public InsertClass(Context context, EditText edt)
{
this.context = context;
pDialog = new ProgressDialog(context);
this.edt = edt;
}
@Override
protected void onPreExecute() {
pDialog.setMessage("Loading... Please wait");
pDialog.show();
super.onPreExecute();
}
@Override
protected String doInBackground(String... arg0) {
try
{
String username = (String)arg0[0];
String password = (String)arg0[1];
String link = "http://10.0.2.2:8020/test/test.php";
String data = URLEncoder.encode("username","utf-8") +
"=" + URLEncoder.encode(username,"utf-8");
data += "&" + URLEncoder.encode("password","utf-8") +
"=" + URLEncoder.encode(password,"utf-8");
URL url = new URL(link);
URLConnection conn = url.openConnection();
conn.setDoOutput(true);
OutputStreamWriter wr = new OutputStreamWriter(conn.getOutputStream());
wr.write(data);
wr.flush();
BufferedReader reader = new BufferedReader
(new InputStreamReader(conn.getInputStream()));
StringBuilder sb = new StringBuilder();
String line = null;
while((line = reader.readLine()) != null)
{
sb.append(line);
break;
}
json = sb.toString();
jObj = new JSONObject(json);
edt.setText(jObj.getString("id"));
return sb.toString();
}
catch(JSONExeption e)
{
return new String("Exeption: " + e.getMessage());
}
catch(Exception e)
{
return new String("Exeption: " + e.getMessage());
}
}
@Override
protected void onPostExecute(String result) {
pDialog.dismiss();
super.onPostExecute(result);
}
}
MainActivity.java
package com.example.testphp;
import android.os.Bundle;
import android.app.Activity;
import android.view.Menu;
import android.view.View;
import android.view.View.OnClickListener;
import android.widget.Button;
import android.widget.EditText;
public class MainActivity extends Activity {
String username;
String password;
EditText edtUsername;
EditText edtPassword;
EditText edtResult;
Button btnInsert;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
btnInsert = (Button) findViewById(R.id.btn_insert);
edtPassword = (EditText) findViewById(R.id.edt_password);
edtUsername = (EditText) findViewById(R.id.edt_username);
edtResult = (EditText) findViewById(R.id.edt_result);
btnInsert.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View arg0) {
username = edtUsername.getText().toString();
password = edtPassword.getText().toString();
new InsertClass(MainActivity.this, edtResult).execute(username,password);
}
});
}
@Override
public boolean onCreateOptionsMenu(Menu menu) {
// Inflate the menu; this adds items to the action bar if it is present.
getMenuInflater().inflate(R.menu.main, menu);
return true;
}
}
test.php的
<?php
$con = mysqli_connect("localhost" , "root" , "","test");
if(mysqli_connect_errno($con))
{
echo "Failed to connect to MySQL: " . mysqli_connect_errno();
}
$username = $_POST['username'];
$password = $_POST['password'];
$result = mysqli_query($con,"INSERT INTO test (username,pass) VALUES '$username','$password')");
if($result)
{
$id_result = mysqli_query($con,"SELECT id FROM test WHERE username = $username");
if($id_result)
{
$response = array("id" => $id_result);
echo json_encode($response);
}
}
mysqli_close($con);
?>
任何建議,將不勝感激...
據我所知,您的SQL中有2個錯誤。
該行缺少括號:
$result = mysqli_query($con,"INSERT INTO test (username,pass) VALUES '$username','$password')");
^ bracket
內容應為:
$result = mysqli_query($con,"INSERT INTO test (username,pass) VALUES ('$username','$password')");
該行缺少$username
引號
$id_result = mysqli_query($con,"SELECT id FROM test WHERE username = $username");
內容應為:
$id_result = mysqli_query($con,"SELECT id FROM test WHERE username = '$username'");
在mysqli_query()
添加or die(mysqli_error($con))
mysqli_query()
以查看實際錯誤。
您還應該防止SQL注入,將POST變量更改為:
$username = stripslashes($_POST['username']);
$username = mysqli_real_escape_string($con, $_POST['username']);
$password = stripslashes($_POST['password']);
$password = mysqli_real_escape_string($con, $_POST['password']);
用預處理語句研究mysqli
或用預處理語句研究PDO , 它們更加安全 。
我將無法為您提供Android代碼,但請參閱Selvin在評論中提到的內容:
“您正在捕獲異常,對此不采取任何措施(至少要執行
e.printStackTrace()
才能在Logcat中看到它)……而且我很確定您觸摸不良會傷害到UI,UI不願意從非UI線程被感動”
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