解析器：移動指令預期的指令

Question

我正在嘗試制作一個簡單的匯編程序，即將兩個數字相加並顯示它們，然后將兩個數字相減並顯示它們。 但是我遇到了錯誤：

oppgave3.asm:28: error: parser: instruction expected
oppgave3.asm:29: error: comma, colon, decorator or end of line expected after operand
oppgave3.asm:30: error: symbol `move' redefined
oppgave3.asm:30: error: parser: instruction expected
oppgave3.asm:31: error: comma, colon, decorator or end of line expected after operand
oppgave3.asm:32: error: comma, colon, decorator or end of line expected after operand
oppgave3.asm:33: error: comma, colon, decorator or end of line expected after operand
oppgave3.asm:37: error: symbol `move' redefined
oppgave3.asm:37: error: parser: instruction expected
oppgave3.asm:38: error: comma, colon, decorator or end of line expected after operand
oppgave3.asm:39: error: symbol `move' redefined
oppgave3.asm:39: error: parser: instruction expected
oppgave3.asm:40: error: comma, colon, decorator or end of line expected after operand
oppgave3.asm:41: error: comma, colon, decorator or end of line expected after operand
oppgave3.asm:42: error: comma, colon, decorator or end of line expected after operand

這就是我想要做的：我有兩個子程序，一個用於加法，一個用於減法。

section .data
a dw 4
b dw 2


section .bss
c resb 1

section .text
global_start:
_start:

call addition
mov eax,4
mov ebx,1
mov ecx,c
mov edx,1
int 0x80

call subtraction
mov eax,4
mov ebx,1
mov ecx,c
mov edx,1
int 0x80

addition:
move eax,[a]
sub eax '0'
move ebx,[b]
sub ebx '0'
add eax and ebx
add eax '0'
mov [c],eax
ret

subtraction:
move eax,[a]
sub eax '0'
move ebx,[b]
sub ebx '0'
sub eax and ebx
add eax '0'
mov [c],eax
ret

Answer 1

你寫的是“move”而不是“mov”

未被識別為指令助記符的標記被視為標簽。 就像move nop等價於move: nop 。 這就是為什么您會在一些后來的用途中symbol 'move' redefined " symbol 'move' redefined的原因。

還有其他各種語法錯誤，例如sub eax and ebx而不是sub eax, ebx和sub ebx '0'缺少逗號

Answer 2

我想你有一個錯字。 你有一個“移動”指令，而我的猜測是它應該是“移動”，最后沒有額外的 e 。 我不是裝配專家，所以我在這里可能是錯的。