[英]Caesar Cipher issue (C)
此代碼的目的是創建一個Caesar密碼,只用3個密鑰對字母數字字符進行編碼,其中第一個字母由第一個鍵增加,第二個字符由第二個鍵增加,第三個字符由第三個鍵增加,第四個字符由第一個鍵增加密鑰等...用環繞(Z + 1 - > a),(a - 1 - > Z)。
我完全完成了作業,唯一的問題是我的負面包裹不起作用(a - 1 - > Z)。 它要求輸入密鑰,接受輸入,然后不返回任何內容(但仍然允許用戶鍵入並按Enter鍵而不會產生任何結果)。 這是我的代碼:
#include <stdio.h>
#include <math.h>
#include <string.h>
#include <stdlib.h>
char sentence[101] = { '\0' };
char alphabet[52]={'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z','A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z'};
int locateletter(char tolocate){
int i=0;
for(i=0; i<52; i++){
if(alphabet[i] == tolocate)
return i;
}
}
int main(void){
int key1 = 0;
int key2 = 0;
int key3 = 0;
printf("Sentence: ");
scanf("%101[^\n]", sentence);
if( sentence[100] != '\0' ){
printf("You entered more than 100 characters. Block Caesar Cipher is exiting. Goodbye.\n");
exit;
}else{
printf("Keys: ");
scanf("%d %d %d", &key1, &key2, &key3);
int i=0;
for(i=0; i<100; i=i+3){
if(isalpha(sentence[i])){
int position = locateletter(sentence[i]);
while((position+key1)>51){
key1 = position+key1-52;
position=0;
}
while((position+key1)<0){
key1 = key1+position+52;
position=0;
}
sentence[i] = alphabet[position+key1];
}
}
int k=1;
for(k=1; k<100; k=k+3){
if(isalpha(sentence[k])){
int position = locateletter(sentence[k]);
while((position+key2)>51){
key2 = position+key2-52;
position=0;
}
while((position+key2)<0){
key1 = key2+position+52;
position=0;
}
sentence[k] = alphabet[position+key2];
}
}
int t=2;
for(t=2; t<100; t=t+3){
if(isalpha(sentence[t])){
int position = locateletter(sentence[t]);
while((position+key3)>51){
key3 = position+key3-52;
position=0;
}
while((position+key3)<0){
key1 = key3+position+52;
position=0;
}
sentence[t] = alphabet[position+key3];
}
}
printf("Cipher: %s\nDone.\n", sentence);
}
return 0;
}
我發現了錯誤。 我的負循環for negative wrap將值分配給key1而不是key2 / 3。
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