根據MySQL結果在PHP while循環中每1和4一次運行腳本

Question

我有一個while loop從MySQL表中獲取數據。 返回的行數未知。 我想在每個第1和第4個項目中在loop內運行部分代碼，例如：

while ($result = $stmt->fetch()) {

   //Run on first row always, then repeat on the 4th item and so on.
   echo '<div class="row">';

}

我怎樣才能做到這一點？

Answer 1

// keep track of the iteration count
$i = 1;

while ($result = $stmt->fetch()) {

    //if it's the first iteration, open the row
    if($i == 1) { echo '<div class="row">'; }

    //...

    // NOTE: count($results) is pseudocode, make sure you provide it somehow
    // if you're on the 4nth or the last iteration 
    if($i % 4 == 0 or $i == count($results))
    {
        // close the row
        echo '</div>';

        // if it's not the last item in the loop, open a new row
        if($i != count($results)) { echo '<div class="row">'; }
    }

    $i++;
}