如何從字符串獲取url-jQuery或Javascript

Question

我有這樣的網址：

http://192.168.6.1/Images/Work3ererg.png
http://192.168.6.1/Images/WorwefewfewfefewfwekThumb.png
http://192.168.6.1/Images/ewfefewfewfewf23243.png
http://192.168.6.1/Images/freferfer455ggg.png
http://192.168.6.1/Images/regrgrger54654654.png

我想從這些url知道http://192.168.6.1 ...如何使用jquery或javascript實現此目的？

我要做什么？

i got this string from my JavaScript :  http://192.168.6.1/Images/Work3ererg.png

使用這個javscript字符串：

我想放**https://192.168.6.1/**而不是**http://localhost:37774**包括http

$("#" + id).css("background", "rgba(0, 0, 0, 0) url(http://localhost:37774/Images/PBexVerticalLine1.png) no-repeat scroll 0% 0% / auto padding-box border-box")

謝謝

Answer 1

var url = 'http://192.168.6.1/Images/Work3ererg.png';
var host = url.substr(0,url.indexOf('/',7));

url.indexOf('/',7)表示在http://之后搜索/

然后用substr得到的字符串從開始到第一/后http://

Answer 2

如果支持瀏覽器（IE 10及更高版本和最新瀏覽器），則可以使用URL對象 。

您只需要這樣做：

var test = new URL('http://192.168.6.1/Images/regrgrger54654654.png')
console.log(test.origin)

如果要使用正則表達式，則可以在這種情況下使用它：

var url = 'http://192.168.6.1/Images/regrgrger54654654.png'

console.log(url.match(/https?:\/{2}[^\/]*/)[0]);

http://jsfiddle.net/8cd67Lzs/

Answer 3

擴展答案來自： https : //stackoverflow.com/a/736970/1026017

var getHostname = function(href) {
    var l = document.createElement("a");
    l.href = href;
    return l.hostname;
};

Answer 4

只需將字符串的一部分替換為另一個字符串：

var originalString = "http://192.168.6.1/Images/freferfer455ggg.png";
var newString = originalString.replace("http://192.168.6.1/","https://192.168.6.1/");
console.log(newString);

Answer 5

您可以使用RegularExpression （純JavaScript）來完成此工作，例如，您可以使用

var ip = ''; // will contain the ip address
var ips = [] // ips is an array  that will contain all the ip address

var url = 'http://192.168.6.1/Images/Work3ererg.png';

url.replace(/http:\/\/(.+?)\//,function(all,first){
            // first will be something like 192.168.6.1
            // while all  will be something like http://192.168.6.1
            ip = first;
});

// url can be a a list of ip address in this case we should add the 
// g flag(which means global, not just the first match but all the matches )


url  ='http://192.168.6.1/Images/Work3ererg.png';
url +='http://192.168.6.2/Images/Work3ererg.png';

url.replace(/http:\/\/(.+?)\//g,function(all,first){
           ips.push(first);
});