Python3.3 HTML Client TypeError：'str'不支持緩沖區接口

Question

import socket

# Set up a TCP/IP socket
s = socket.socket(socket.AF_INET,socket.SOCK_STREAM)

# Connect as client to a selected server
# on a specified port
s.connect(("www.wellho.net",80))

# Protocol exchange - sends and receives
s.send("GET /robots.txt HTTP/1.0\n\n")
while True:
        resp = s.recv(1024)
        if resp == "": break
        print(resp,)

# Close the connection when completed
s.close()
print("\ndone")

錯誤：

cg0546wq@smaug:~/Desktop/440$ python3 HTTPclient.py
Traceback (most recent call last):
  File "HTTPclient.py", line 11, in <module>
    s.send("GET /robots.txt HTTP/1.0\n\n")
TypeError: 'str' does not support the buffer interface

不能用

• urllib.request.urlopen
• urllib2.urlopen
• http
• http.client
• httplib

Answer 1

套接字只能接受字節 ，而您嘗試向其發送Unicode字符串。

將字符串編碼為字節：

s.send("GET /robots.txt HTTP/1.0\n\n".encode('ascii'))

或者給它一個字節文字（以b前綴開頭的字符串文字）：

s.send(b"GET /robots.txt HTTP/1.0\n\n")

考慮到您收到的數據也將是bytes值; 你不能只將它們與''進行比較。 只測試一個空響應，你可能想要在打印時解碼對str的響應：

while True:
    resp = s.recv(1024)
    if not resp: break
    print(resp.decode('ascii'))

Answer 2

import socket

# Set up a TCP/IP socket
s = socket.socket(socket.AF_INET,socket.SOCK_STREAM)

# Connect as client to a selected server
# on a specified port
s.connect(("www.google.com",80))

# Protocol exchange - sends and receives
s.send(b"GET /index.html HTTP/1.0\n\n")
while True:
        resp = s.recv(1024)
        if resp == b'': break
        print(resp,)

# Close the connection when completed
s.close()
print("\ndone")