Primefaces文件上傳-ZipFile錯誤

Question

當我使用zipfile上傳到文件時，出現此錯誤。

錯誤： Error creating zip file: java.io.FileNotFoundException: C:\\fupload\\qhT39xmU- (The system cannot find the file specified)

這是我的上傳方法：

public String uploadToFts(UploadedFile filem, String fileType){
    String fileFtsUrl =   null;
    String uploadUrl = fileDAO.findByUniqueProperty("name", "geturl").getPropValue();
    String usr= fileDAO.findByUniqueProperty("name", "usr").getPropValue();
    String pwd= fileDAO.findByUniqueProperty("name", "pwd").getPropValue();
    String nameId= String.valueOf(passGen.create(1, 1, 8, 8, 0)) + "-";
    try{
        ClientConfig cc = new DefaultClientConfig();
        Client client = Client.create(cc);
        client.addFilter(new HTTPBasicAuthFilter(usr, pwd));
        try {
            FormDataMultiPart form = new FormDataMultiPart();
            File file = new File("C:/fupload/"+nameId+"");
            File thumbnail = new File("C:/fupload/"+nameId+"-tmb.jpg");
            zipFile("C:/fupload/"+nameId+".zip", file, thumbnail);
            File zipFile = new File("C:/fupload/"+nameId+".zip");
            String urlParams = "nameId=" + nameId+ "&" +
                    "fileType="+fileType+"&" +
                    "fileName=" + zipFile.getName() + "&" +
                    "zipped=true";
            form.bodyPart(new FileDataBodyPart("file", zipFile, MediaType.MULTIPART_FORM_DATA_TYPE));
            WebResource resource = client.resource(uploadUrl + urlParams);
            ClientResponse response = resource.type(MediaType.APPLICATION_OCTET_STREAM).put(ClientResponse.class, zipFile);
            String respStr = response.getEntity(String.class);
            if(respStr.contains("\"status\":0")){
                System.out.println(respStr);
                JSONObject obj = new JSONObject(respStr);
                int jsonStatus = obj.getInt("status");
                int jsonTxnId = obj.getInt("txnid");
                String url = obj.getString("url");

                fileFtsUrl =  url;
            }   else {
                addMessageToView(FacesMessage.SEVERITY_ERROR, "", "Can't uploading FTS"+respStr);
            }
        } catch (Exception e) {
            e.printStackTrace();
        }
         return fileFtsUrl;
    }   catch (Exception e){
        e.printStackTrace();
        return fileFtsUrl;
    }
}

ZipFile方法

public static void zipFile(String zipFile, File... srcFiles) {
    try {
        // create byte buffer
        byte[] buffer = new byte[1024];
        FileOutputStream fos = new FileOutputStream(zipFile);
        ZipOutputStream zos = new ZipOutputStream(fos);
        for (int i = 0; i < srcFiles.length; i++) {
            File srcFile = srcFiles[i];
            FileInputStream fis = new FileInputStream(srcFile);
            // begin writing a new ZIP entry, positions the stream to the start of the entry data
            zos.putNextEntry(new ZipEntry(srcFile.getName()));
            int length;
            while ((length = fis.read(buffer)) > 0) {
                zos.write(buffer, 0, length);
            }
            zos.closeEntry();
            // close the InputStream
            fis.close();
        }
        // close the ZipOutputStream
        zos.close();
    } catch (IOException ioe) {
        System.out.println("Error creating zip file: " + ioe);
    }
}

Answer 1

我認為您只需要在zipFile（..）中創建文件，因為它將不存在：

File file = new File(zipFile);
if(!file.exists()) {
    file.createNewFile();
} 
FileOutputStream fos = new FileOutputStream(file, false); 

也許最好在之前創建它並將其傳遞給zipFile（file，...），這樣您就不必在調用之后再次創建它。 因此，與其他參數一樣，傳遞File而不是String 。

Answer 2

檢查與

 System.out.println("C:/fupload/"+nameId+"")

 System.out.println("C:/fupload/"+nameId+"-tmb.jpg")

系統中是否存在？

確保您的路徑必須指向系統中的文件