php imagejpeg（）：無法打開“ /pic/upload/123.jpg”進行寫入：無此類文件或目錄

Question

幾天以來，我一直在尋找如何解決該問題的方法，並嘗試了所有在這里找到的方法。 我不是很擅長php，所以我希望這里的人比我更快地發現問題:)

許可在777上圖片被上傳到/ pic / tmp ...而且我還試圖更改為上傳到/ pic，多數民眾贊成在沒有任何問題的情況下.......僅當我想對imagejpeg（）

感謝幫助！

（有些嘗試已經用// ...標記了，但是我嘗試的並不是全部）

<?php
$ftp_server = "adress";
$ftp_user_name = "user";
$ftp_user_pass = "password";

$destination_file = "/pic/upload/tmp/". basename($_FILES['file']['name']);
$uploaddir="/pic/upload/tmp/";
$newpath="/pic/upload/";
$ftppath="ftp://".$ftp_user_name.":".$ftp_user_pass."@".$ftp_server;
$source_file = $_FILES['file']['tmp_name'];

$conn_id = ftp_connect($ftp_server);
ftp_pasv($conn_id, true); 
$login_result = ftp_login($conn_id, $ftp_user_name, $ftp_user_pass); 

$upload = ftp_put($conn_id, $destination_file, $source_file, FTP_BINARY); 

$alterPfad=$ftppath.$uploaddir."123.jpg";
$neuerPfad=$newpath."123.jpg";
//$neuerPfad=$ftppath.$newpath."123.jpg";
//$neuerPfad=".".$newpath."123.jpg";

$bildEigenschaft = getimagesize($alterPfad); 
$widthOld = $bildEigenschaft[0]; 
$heightOld = $bildEigenschaft[1]; 
$image_filetype = $bildEigenschaft[2]; 

$width=$widthOld;
$height=$heightOld;
    if($width>670)
        {list($width,$height)=Groessenberechnung($width,$height,670);
        }
    if($height>500)
        {echo "<p>berechnung 2.1 weite:".$width." hoehe:".$height."</p>";
        list($height,$width)=Groessenberechnung($height,$width,500);
        }

$image_old = imagecreatefromjpeg($alterPfad); 
$image_new = imagecreatetruecolor($width, $height); 

imagecopyresampled($image_new, $image_old, 0, 0, 0, 0, $width, $height, $widthOld, $heightOld); 

//tp_rename($conn_id,$destination_file,$uploaddir."123.jpg");   //ftp_put($conn_id,"/pic/upload/123.jpg","/pic/upload/tmp/123.jpg", FTP_BINARY); 
//ftp_raw($conn_id,imagejpeg($image_new,$neuerPfad)); 
    imagejpeg($image_new,$neuerPfad);
...
...
...
?>

Answer 1

我將echo顯$neuerPfad的值，以查看它嘗試打開的路徑。