mySQL - 使用三個表中的數據和列創建新表

Question

我正在嘗試創建一個新表，該表將由來自三個現有表的選定數據組成。

現有的三個表設置如下，我想要的結果在底部：

people
id      last_name   first_name  email
1       Smith       Fred        Fred@..
2       Jones       Tom         Tom@..
3       Doe         Jane        Jane@..

taxonomy
id      taxonomy    
1       age
2       gender
3       height

details
id      person_id   detail_id   content
1       1           1           36
2       1           2           M
3       1           3           5'10"
4       2           1           29
5       2           2           M
6       2           3           6'3"
7       3           1           27
8       3           2           F
9       3           3           5'8"


New Table
id      last_name   first_name  email   age
1       Smith       Fred        Fred@.. 36
2       Jones       Tom         Tom@..  29
3       Doe         Jane        Jane@.. 27

在此先感謝您的幫助！

Answer 1

您需要進行 3 向 JOIN：

CREATE TABLE new_table AS
SELECT p.*, d.content AS age
FROM people AS p
JOIN details AS d ON d.person_id = p.id
JOIN taxonomy AS t ON t.id = d.detail_id
WHERE t.taxonomy = 'age'

演示

或者，如果您已經創建了表，則可以執行以下操作：

INSERT INTO new_table (id, last_name, first_name, email, age)
SELECT p.id, p.last_name, p.first_name, p.email, d.content AS age
FROM people AS p
JOIN details AS d ON d.person_id = p.id
JOIN taxonomy AS t ON t.id = d.detail_id
WHERE t.taxonomy = 'age'

要獲得多個屬性，您必須為每個屬性分別加入詳細信息和分類表：

CREATE TABLE new_table AS
SELECT p.*, d1.content AS age, d2.content AS gender, d3.content AS height
FROM people AS p
JOIN details AS d1 ON d1.person_id = p.id
JOIN taxonomy AS t1 ON t1.id = d1.detail_id
JOIN details AS d2 ON d2.person_id = p.id
JOIN taxonomy AS t2 ON t2.id = d2.detail_id
JOIN details AS d3 ON d3.person_id = p.id
JOIN taxonomy AS t3 ON t3.id = d3.detail_id
WHERE t1.taxonomy = 'age' AND t2.taxonomy = 'gender' AND t3.taxonomy = 'height'