[英]How do you make a loop with switch statements in c++?
忍受我,我還是C ++的新手...
因此,我的困境是我有兩個游戲的菜單,兩個菜單都在各自的switch語句/案例中。 該代碼有效,但是一旦完成,它將關閉游戲。 我一輩子都想不通如何回到我選擇游戲的主菜單。
我的代碼如下:
#include<iostream>
#include<string>
#include<cstdlib>
#include<ctime>
#include<iomanip>
using namespace std;
int main()
{
string name;
int choice; //the choices for the menu
char sym; //part of the menu
int number = rand() % 10 + 1; //sets number to a random number between 1-10
int digit; // part of the math game
bool menu = true;
int guessNum; //number that user guesses
int i; //loop variable
bool guessRight = false;
char answer = 'y';
/questions omitted
while (menu){ //start of loop and will come back here after each game finishes
cout << setfill(sym) << setw(55);
cout << "\n";
cout << "\t Welcome," << ' ' << name << endl;
cout << "Please choose a number from the following options:" << endl; //Gives the user the options to input using numbers.
cout << "\n";
cout << "\t1. Play the math game!" << endl;
cout << "\t2. Play the guessing game!" << endl;
cout << "\t3. Exit" << endl;
cout << setfill(sym) << setw(55);
cout << "\n";
cin >> choice; //The user gets to input numbers 1-3 at this point
switch (choice)
{
case 1:
//Math game here
break;
case 2:
//random number game here
break;
case 3: //exits the program
cout << "I guess we're done here." << endl;
return 0;
}
}
}
我已經省略了游戲本身,但是我對如何在完成游戲后從兩個游戲返回到主菜單感到困惑。 完成后,我將提示用戶“返回菜單?是/否”。 我懷疑我必須插入一個do-while循環,但是我不確定該怎么做。 我感謝任何建議!
該代碼完全符合您的要求! 它要求用戶提供一個選項,然后,除了給出選項3之外,返回到菜單的開頭。
這是因為您有:
bool menu = true;
while (menu) {
// your print and games
// no modification of 'menu'
}
另請注意:
cout << setfill(sym) << setw(55); // 'sym' is NOT initialized here.
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