[英]getting integer from JSON data in java
我嘗試從JSON數據獲取整數。 但是每當調用該方法時,都會出現錯誤:
Undeterminated object at character 16 of {"lat": 47175650
這是我的JSON數據: [{"lat": 47175650, "lon": 7637853}]
這是我讀取數據的代碼。 它適用於Android應用程序,它從文件獲取數據,將JSON數組中的所有對象放入字符串數組,並應創建與對象一樣多的GeoPoint:
public void loadData(){
File f = new File("/data/data/com.example.app/files/file.txt");
if (f.exists()) {
String locations = null;
try {
FileInputStream loadLoc = openFileInput("file.txt");
List<Byte> data = new ArrayList<Byte>();
while (true) {
int b = loadLoc.read();
if (b == -1)
break; // end of file
else
data.add((byte) b);
}
// bytes to string
byte[] bytes = new byte[data.size()];
for (int i = 0; i<bytes.length; i++)
bytes[i] = data.get(i);
locations = new String(bytes);
Log.e("debug", locations);
loadLoc.close();
} catch (Exception ex) {
Log.e("debug", ex.getMessage());
}
locations = locations.substring(1, locations.length()-1);
String[] points = locations.split(",");
JSONObject json;
GeoPoint p;
try {
for (int i=0; i<points.length; i++) {
json = new JSONObject(points[i]);
// I guess the "getInt()"s here are the problem
p = new GeoPoint(json.getInt("lat"), json.getInt("lon"));
overlay.addItem(p, "location", "location");
}
} catch (JSONException ex) {
Log.e("debug", ex.getMessage());
}
}
}
我的猜測是我必須將數字放在引號中,但是我必須以該格式保護數據(在引號中沒有整數),而且我知道我的數據是有效的JSON。
您正在拆分JSONObject。 因此[{"lat": 47175650, "lon": 7637853}]
成為兩個字符串{"lat": 47175650
和"lon": 7637853}
。
看來您的數據存儲為JSONArray。 因此,更換
locations = locations.substring(1, locations.length()-1);
String[] points = locations.split(",");
JSONObject json;
GeoPoint p;
try {
for (int i=0; i<points.length; i++) {
json = new JSONObject(points[i]);
// I guess the "getInt()"s here are the problem
p = new GeoPoint(json.getInt("lat"), json.getInt("lon"));
overlay.addItem(p, "location", "location");
}
} catch (JSONException ex) {
Log.e("debug", ex.getMessage());
}
同
try {
JSONArray array = new JSONArray(locations);
for(int i = 0; i < array.length(); i++) {
JSONObject json = array.getJSONObject(i);
GeoPoint p = new GeoPoint(json.getInt("lat"), json.getInt("lon"));
overlay.addItem(p, "location", "location");
}
} catch (JSONException ex) {
Log.e("debug", ex.getMessage());
}
您是否曾嘗試將其讀取為字符串,然后將其轉換為整數? 我的意思是:
p = new GeoPoint(Integer.valueOf(json.getString("lat")), Integer.valueOf( json.getString("lon")));
您應該首先將JSON-String解析為JSONArray
。
JSONArray points = new JSONArray(locations);
int length = points.length();
for (int i = 0; i < length; ++i) {
JSONObject point = points.getJSONObject(i);
int lat = point.getInt("lat");
int lon = point.getInt("lon");
}
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