JPA-加入同一張桌子

Question

我收到了這個請求：

TypedQuery<ParamGenerauxExternes> q = entityMgr
            .createQuery("SELECT p FROM ParamGenerauxExternes p "
                    + "WHERE EXISTS "
                    + "(SELECT q FROM ParamGenerauxExternes q "
                    + "WHERE q.key.origine = :pOrigine "
                    + "AND q.key.typeParam LIKE :pTypeParametreBis "
                    + "AND p.key.sousType LIKE CONCAT('%',q.libelleParam) "
                    + "AND q.actif = 'Y') "
                    + "ORDER BY p.libelleParam", ParamGenerauxExternes.class)
            //.setParameter("pTypeParametre", "REL_TO_HOUSEHOLD")
            .setParameter("pOrigine", pOrigineGrc)
            .setParameter("pTypeParametreBis", "GRC_HOUSEHOLD_TYPE_P%");

但這不起作用，我得到了一條錯誤消息，告訴我們缺少一個假牙：

GRAVE: EJB Exception: : javax.persistence.PersistenceException: org.hibernate.exception.SQLGrammarException: ORA-00907: missing right parenthesis

在第二次選擇之后，JPA生成的SQL帶有括號：

select
    paramgener0_.CODE_PARAM as CODE1_2823_,
    paramgener0_.ORIGINE as ORIGINE2823_,
    paramgener0_.SOUS_TYPE as SOUS3_2823_,
    paramgener0_.TYPE_PARAM as TYPE4_2823_,
    paramgener0_.ACTIF as ACTIF2823_,
    paramgener0_.LIBELLE_PARAM as LIBELLE6_2823_ 
from
    FOA_PARAM_GEN_EXTERNE paramgener0_ 
where
    exists (
        select
            (paramgener1_.CODE_PARAM,
            paramgener1_.ORIGINE,
            paramgener1_.SOUS_TYPE,
            paramgener1_.TYPE_PARAM) 
        from
            FOA_PARAM_GEN_EXTERNE paramgener1_ 
        where
            paramgener1_.ORIGINE=? 
            and (
                paramgener1_.TYPE_PARAM like ?
            ) 
            and (
                paramgener0_.SOUS_TYPE like '%'||paramgener1_.LIBELLE_PARAM
            ) 
            and paramgener1_.ACTIF='Y'
    ) 
order by
    paramgener0_.LIBELLE_PARAM

我不知道為什么冬眠第二select后添加括號？ 如果您知道該怎么辦，請...

Answer 1

該查詢在Oracle上失敗，但會繼續傳遞，例如Postgres。 如果使用的是Oracle數據庫，請嘗試將Oracle SQL方言設置為JPA提供程序。
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