[英]Issues in using circular linked list for a clock
所以我得到了制作數字時鍾所需的這項工作。 用戶設置點頭的數量,每個點頭等於1 / n秒,N是用戶點頭的數量,之后我被要求做出3個指針:
Seconds指針必須在循環鏈接中運行所有的點頭。 對於完整旋轉,分鍾指針應開始移動到下一個節點,並且分鍾指針總共移動60次后,小時指針應緊隨其后。 時鍾需要執行以下操作:
用戶可以將時鍾設置回零:00:00:00;
用戶可以以秒為單位設置時鍾。
該程序需要在每次活動后顯示時鍾。
用戶可以為鬧鍾編程時鍾,其中時鍾向用戶顯示一條消息。
它需要找到其指針(不是程序的時鍾)對齊的下一小時(例如:12:00,01:05,02:10,03:15等)
這是我的代碼,但是我遇到了一些困難。
#include<stdio.h>
#include<stdlib.h>
int counter=0;
typedef struct Node
{
int data;
struct Node *next;
}node;
void insert(node *pointer, int data)
{
node *start = pointer;
/* Iterate through the list till we encounter the last node.*/
while(pointer->next!=start)
{
pointer = pointer -> next;
}
/* Allocate memory for the new node and put data in it.*/
pointer->next = (node *)malloc(sizeof(node));
pointer = pointer->next;
pointer->data = data;
pointer->next = start;
}
void print(node *start,node *pointer)
{
if(pointer==start)
{
return;
}
printf("%d ",pointer->data);
print(start,pointer->next);
}
int main()
{
/* start always points to the first node of the linked list.
temp is used to point to the last node of the linked list.*/
node *start,*temp;
start = (node *)malloc(sizeof(node));
temp = start;
temp -> next = start;
/* Here in this code, we take the first node as a dummy node.
The first node does not contain data, but it used because to avoid handling special cases
in insert and delete functions.
*/
node *sec,*min,*hour;
int v,c,n;
printf("1. Insert N\n");
printf("2. Make Time Zero\n");
printf("3. Set Clock\n");
int query;
scanf("%d",&query);
if(query==1)
{
int data,i,n;
printf("Posa n thes\n");
scanf("%d",&n);
for (i = 0; i < 60*n; i++)
{
data = i;
insert(start,data);
printf("%d\n",i);
}
node *sec_copy;
sec_copy=start;
min=start;
hour=start;
while(n>0)
{
sec_copy=sec_copy->next;
n--;
c++;
if(c == 59*n)
{
min=min->next;
c=0;
v++;
}
if(v == 60)
{
hour=hour->next;
v=0;
}
}
}
printf("%d",sec->data);
if(query==2)
{
int timer;
timer=0;
printf("%.2d:%.2d:%.2d",timer,timer,timer);
}
if(query==3)
{
int h,m,s;
printf("Set me hours");
scanf("%d",&h);
h = h%24;
printf("Set me min");
scanf("%d",&m);
h = h+m/60;
m = m%60;
printf("Set me secs");
scanf("%d",&s);
h = h + s/3600;
m = m + s%3600;
s = s%60;
}
}
正如Jochaim Pileborg指出的那樣,您確實需要使用調試器。
我看到的段錯誤的唯一原因是您調用: printf("%d",sec->data);
無需初始化sec
。
您也不會初始化'v'和'c',並且解決方案中有兩個'n'變量。
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