無效的HTML-引用屬性

Question

我有以下HTML：

<td width=140 style='width:105.0pt;padding:0cm 0cm 0cm 0cm'>
    <p class=MsoNormal><span style='font-size:9.0pt;font-family:"Arial","sans-serif";
       mso-fareast-font-family:"Times New Roman";color:#666666'>OCCUPANCY
       TAX:</span></p>
</td>

未引用某些HTML屬性，例如：width = 140和class = MsoNormal

如果沒有的話，是否有任何PHP函數可以解決此類問題，如果不是，那么用HTML進行清理的聰明方法是什么？

謝謝。

Answer 1

我猜你可以為此使用正則表達式：

/\s([\w]{1,}=)((?!")[\w]{1,}(?!"))/g


\s match any white space character [\r\n\t\f ]
1st Capturing group ([\w]{1,}=)
    [\w]{1,} match a single character present in the list below
        Quantifier: {1,} Between 1 and unlimited times, as many times as possible, giving back as needed [greedy]
    \w match any word character [a-zA-Z0-9_]
    = matches the character = literally
2nd Capturing group ((?!")[\w]{1,}(?!"))
    (?!") Negative Lookahead - Assert that it is impossible to match the regex below
    " matches the characters " literally
    [\w]{1,} match a single character present in the list below
        Quantifier: {1,} Between 1 and unlimited times, as many times as possible, giving back as needed [greedy]
    \w match any word character [a-zA-Z0-9_]
    (?!") Negative Lookahead - Assert that it is impossible to match the regex below
    " matches the characters " literally
g modifier: global. All matches (don't return on first match)

可以這樣實現：

echo preg_replace_callback('/\s([\w]{1,}=)((?!")[\w]{1,}(?!"))/', function($matches){
    return ' '.$matches[1].'"'.$matches[2].'"';
}, $str);

並導致：

 <td width="140" style='width:105.0pt;padding:0cm 0cm 0cm 0cm'>
   <p class="MsoNormal"><span style='font-size:9.0pt;font-family:"Arial","sans-serif";
     mso-fareast-font-family:"Times New Roman";color:#666666'>OCCUPANCY
      TAX:</span></p>
 </td>

現場實例評估

注意，這是一個骯臟的例子，可以肯定地將其清除。