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將參數傳遞給doGet()Servlet

[英]Passing parameter to doGet() servlet

嘗試通過Servlet從Android訪問MySQL時遇到問題。 我正在嘗試通過將某些值傳遞給Servlet類來檢查事件是否存在於數據庫中。 如果沒有現有記錄,則執行數據庫插入。

    public void createEvent(Event event) {
    String page;
    JSONArray jsonArray;
    try {
        HttpClient client = new DefaultHttpClient();
        HttpGet request = new HttpGet(ENeighbourhoodActivity.URL + "checkEventExist");
        List<NameValuePair> checkExistnvp = new ArrayList<NameValuePair>(3);
        checkExistnvp.add(new BasicNameValuePair("eventName", event.getEventName()));
        checkExistnvp.add(new BasicNameValuePair("eventX", event.getEventX()));
        checkExistnvp.add(new BasicNameValuePair("eventY", event.getEventY()));

        try {
            post.setEntity(new UrlEncodedFormEntity(checkExistnvp));
        } catch (UnsupportedEncodingException e) {
            e.printStackTrace();
        }

        HttpResponse response = client.execute(request);
        HttpEntity entity = response.getEntity();
        String responseString = EntityUtils.toString(entity, "UTF-8");
        page = "{\'Events\':" + responseString + "}";
        try {
            JSONObject jsonObject = new JSONObject(page);
            jsonArray = jsonObject.getJSONArray("Events");
            int length = jsonArray.length();
            if(length == 0){
                // If no existing record, then perform DB insertion
            }
        } catch (JSONException e) {
            e.printStackTrace();
        }
    } catch (IOException e) {
        e.printStackTrace();
    }

}

在我的servlet中:

protected void doGet(HttpServletRequest request,
        HttpServletResponse response) throws ServletException, IOException {
    JSONArray jsonArray = new JSONArray();
    PrintWriter out = response.getWriter();
    if (request.getParameter("checkEventExist") != null) {
        String eventX = request.getParameter("eventX");
        String eventY = request.getParameter("eventY");
        String eventName = request.getParameter("eventName");
        try {
            Class.forName("com.mysql.jdbc.Driver");
            Connection con = DriverManager.getConnection(
                    "jdbc:mysql://localhost/mydb", "root", "root");

            PreparedStatement statement = con
                    .prepareStatement("SELECT * FROM event WHERE eventName = '" + eventName + "' AND eventX = '" + eventX + "' AND eventY = '"+ eventY + "'");
            ResultSet result = statement.executeQuery();
            while (result.next()) {
                JSONObject eventInfo = new JSONObject();
                eventInfo.put("eventName", result.getString("eventName"));
                eventInfo.put("eventX", result.getString("eventX"));
                eventInfo.put("eventY", result.getString("eventY"));
                jsonArray.put(eventInfo);
            }
        }

        catch (JSONException je) {
            System.out.println(je.getMessage());
        } catch (Exception exc) {
            System.out.println(exc.getMessage());
        }
        out.println(jsonArray.toString());
    }

}

我不確定如何將名稱/值對傳遞給servlet中的doGet()。 用這行:

post.setEntity(new UrlEncodedFormEntity(checkExistnvp));

這就是我將值傳遞給doPost()的方式。 但是我需要將其傳遞給doGet()。 有指導嗎?

提前致謝。

您應該使用查詢參數,因為HTTP GET不允許在HTTP正文中發送實體。

為了發送HTTP GET的參數,您應該准備一個類似以下的URL:

HttpGet request = new HttpGet(ENeighbourhoodActivity.URL + "checkEventExist?" + 
    "eventName=<eventName>&"+
    "eventX=<eventX>&"+
    "eventY=<eventY>");
HttpResponse response = client.execute(request);

而且您不應該在請求中添加任何NameValuePair

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