C程序三角形

Question

我需要提示用戶輸入數字“ n”，然后在單獨的行中打印打印星，例如，如果用戶輸入5，則應打印以下內容（使用while循環）

*
**
***
****
*****
****
***
**
*

我的代碼沒有輸出

int n, x = 1, y = 1;
printf("enter a number : ");
scanf_s("%d", &n);

while (x <= n){
    x++;
    while (y <= x){

        while (y >= n){
            y--;
            printf("*");
        }
        printf("\n");

    }
    system("pause");
}

}

Answer 1

這應該為您工作：

#include <stdio.h>

int main() {

    int number, count, characterCount;


    printf("Please enter a number:\n>");
    scanf("%d", &number);

    for(count = 1; count <= number; count++) {

        for(characterCount = 1; characterCount <= count; characterCount++)
            printf("*");

        printf("\n");

    }

        for(count = 1; count < number; count++) {

        for(characterCount = number-1; characterCount >= count; characterCount--)
            printf("*");

        printf("\n");

    }


    return 0;
}

評論后編輯：

while循環的解決方案：

#include <stdio.h>

int main() {

    int number, count = 1, characterCount;


    printf("Please enter a number:\n>");
    scanf("%d", &number);

    while(count <= number) {

        characterCount = 1;
        while(characterCount <= count) {
            printf("*");
            characterCount++;
        }

        printf("\n");
        count++;
    }

    count = 1;

    while(count < number) {

        characterCount = number-1;
        while( characterCount >= count) {
            printf("*");
            characterCount--;    
        }

        printf("\n");
        count++;
    }


    return 0;
}

Answer 2

您可以僅使用2個for循環來實現，例如：

int i,k,n,flag=0;
printf("Enter Number of Rows    :");
scanf("%d",&n);
for(i=-n;i<=n;i++)
{
    if(i < 0)
    {
        i = -i;
        flag=1;
    }
    for(k=(n-i)+1;k>0;k--)
    {
        printf("*");
    }
    if(flag==1)
    {
        i=-i;flag=0;
    }
    printf("\n");
}

例如，如果用戶輸入值2 ，它將打印

*
**
***
**
*