Google 應用程序腳本 - 迭代文件夾和子文件夾

Question

我想使用 google apps 腳本遍歷 Google Drive 中文件夾的樹結構。 下面的代碼列出了一些文件夾，但不是全部。 你能建議什么是深入文件夾結構的最佳技術嗎？ 我首先嘗試記錄所有文件夾名稱。

謝謝你。

function test() {
 listSubfolders(DriveApp.getFolderById('FOLDER_ID'));
}

function listSubfolders(parentFolder) {
  var childFolders = parentFolder.getFolders();

 while(childFolders.hasNext()) {
   Logger.log(childFolders.next().getName());
   listSubfolders(childFolders.next());   

 }


}

Answer 1

要訪問子文件夾，您可以通過這種方式進行，

function getSubFolders(parent) {
  parent = parent.getId();
  var childFolder = DriveApp.getFolderById(parent).getFolders();
  while(childFolder.hasNext()) {
    var child = childFolder.next();
    Logger.log(child.getName());
    getSubFolders(child);
  }
  return;
}

function listFolders() {
  var parentFolder = DriveApp.getFolderById("0B1n6YLYwFmK_dUpzRWhDRXNwdWc");
  var childFolders = parentFolder.getFolders();
  while(childFolders.hasNext()) {
    var child = childFolders.next();
    Logger.log(child.getName());
    getSubFolders(child);
  }
}

Answer 2

此 Google Script 將生成包含所有文件和文件夾的 Google Drive Tree。

將此腳本復制到您的腳本編輯器。 從“選擇函數”菜單中選擇函數“genFolderTree”。 將根文件夾名稱“RootDir”更改為函數 genFolderTree() 中的根目錄

var foldername = 'RootDir';

谷歌腳本源代碼 -

function genFolderTree() {

  try {

  var foldername = 'RootDir';
  var folderlisting = 'TreeView_' + foldername;

  var parentFolder = DriveApp.getFoldersByName(foldername).next();


  var ss = SpreadsheetApp.create(folderlisting);
  var sheet = ss.getActiveSheet();
  var frontCell = [];
  sheet.appendRow([foldername]).getCurrentCell().setFontWeight('bold').setFontColor('red');
  frontCell.push(" ");
  getChildNode(parentFolder,sheet,frontCell);
  var files = parentFolder.getFiles();
  while (files.hasNext()) {
    frontCell.push(files.next().getName());
    sheet.appendRow( frontCell);
    frontCell.pop();
    }

  } catch (e) {

    Logger.log(e.toString());

  }

}


function getChildNode(parent,sheet,frontCell) {

  var childFolders = parent.getFolders();
  while (childFolders.hasNext()) {

    var childFolder = childFolders.next();

    frontCell.push(childFolder.getName())
    sheet.appendRow(frontCell);
    sheet.getRange(sheet.getLastRow(), frontCell.length).setFontWeight('bold').setFontColor('red');
    frontCell.pop();
    var files = childFolder.getFiles();
    frontCell.push(" ");
    var start_row = 0;
    var row_no = 0;
    while (files.hasNext()) {
      frontCell.push(files.next().getName());
      sheet.appendRow(frontCell);
      if(row_no==0){
        start_row = sheet.getLastRow();
      }
      row_no=row_no+1;
      frontCell.pop();
    }
    if(row_no>0){
      var range;
      range = sheet.getRange(start_row, frontCell.length,row_no);
      // The row grouping depth is increased by row_no.
      range.shiftRowGroupDepth(1);
    }

    // Recursive call for any sub-folders
    getChildNode(childFolder,sheet,frontCell);
    frontCell.pop();
  }

}

你可以從Github 鏈接下載源代碼

Answer 3

這應該可以解決問題：

function start() {
 folder = DriveApp.getFolderById("0B_5HSTQXtXmsOHBzcnc2dTlkRFU") 
 listFolders(folder)
}

function listFolders(folder) {
  //starting point, we come here from start() or from the bottom of this function



  //check the name
  var name = folder.getName();

  if (name.match("TITL")) { 
     folder.addEditor("somePerson@gmail.com"); 
  }

  //now see if this folder has subfolders
  var subfolders = folder.getFolders();

  //if it has, we call this function again
  while (subfolders.hasNext()) {    
    listFolders(subfolders.next());
  }

}

Answer 4

認為這種方法可能不那么重復。 這會以以下格式輸出完整路徑名：

'/root/目錄/目錄/目錄/...'

在“記錄器”行所在的位置，您可以訪問當前文件夾對象（callingFolder），因此此時您可以在該文件夾上插入任何操作。

function myFunction() {
  var topFolder = DriveApp.getFolderById("0AMBwhqwkCWBbUk9PVA");
  var topPath = "/";
  iterateSubFolders(topFolder, topPath);
}

function iterateSubFolders(callingFolder, callingPath) {

  var callingFolderName = callingFolder.getName();
  var callingFolderFullPath = callingPath + callingFolderName + "/";
  Logger.log(callingFolderFullPath);

  var childSubFolders = callingFolder.getFolders();
  while (childSubFolders.hasNext()) {
      var nextSubFolder = childSubFolders.next();
      iterateSubFolders(nextSubFolder, callingFolderFullPath);
  }
}