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[英]SQL: Must appear in the GROUP BY clause or be used in an aggregate function
[英]Must appear in the GROUP BY clause or be used in an aggregate function (PostgreSQL)
我有這樣的查詢:
select u.fullname ,s.schedate,
sum(case when s.isvisiting =1 then s.isvisiting else 0 end) as visit ,
count(s.custid) as cust,
sum(case when s.isclosing = 1 then s.isclosing else 0 end)as orders
from vmstrschedule s JOIN vmsmsuser u ON u.usercode = s.salesmanid
where u.branchid = 'BLL' group by u.fullname
但它顯示如下錯誤:
必須出現在GROUP BY子句中或在聚合函數中使用
它在MySQL中工作,但是當我在PostgreSQL中嘗試時不起作用。 我想每月顯示這樣的數據:
但是如果我使用此查詢:
select u.fullname,s.schedate,
sum(case when s.isvisiting =1 then s.isvisiting else 0 end) as visit ,
count(s.custid) as cust,
sum(case when s.isclosing = 1 then s.isclosing else 0 end)as orders
from vmstrschedule s JOIN vmsmsuser u ON u.usercode = s.salesmanid
where u.branchid = 'BLL' group by u.fullname,s.schedate
order by u.fullname
它將顯示如下數據:
如果按“工作”的意思是它為每個組任意選擇了一個可能的schedate
值,那是正確的。 但是,postgresql和大多數其他SQL產品希望您明確選擇應選擇的值
如果每個組中的所有值都相同,則將其放在GROUP BY
子句或任意聚合中(例如MAX(s.schedate)
)應該起作用。 如果值不同,請告訴服務器應該選擇哪一個MIN
或MAX
通常比較合適。
select u.fullname ,s.schedate,
sum(case when s.isvisiting =1 then s.isvisiting else 0 end) as visit ,
count(s.custid) as cust,
sum(case when s.isclosing = 1 then s.isclosing else 0 end)as orders
from vmstrschedule s JOIN vmsmsuser u ON u.usercode = s.salesmanid
where u.branchid = 'BLL' group by u.fullname, s.schedate
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