如何在PHP中刪除字符串前后

Question

到目前為止這是我的弦

Birthdays=>Birthday||Birthday for Girlfriend|#|Valentines Day=>Valentine Combos||Valentine Roses||Valentines Day - Feb 14th|#|Occasions=>Thinking of you

我想要下面的輸出

Birthdays=>Birthday||Birthday for Girlfriend|#|Valentines Day=>Valentine Combos||Valentine Roses||Valentines Day|#|Occasions=>Thinking of you

根據上面的輸出，我想從字符串中刪除- Feb 14th 。

注意：-- - Feb 14th該字符串將像某些時間一樣是動態的-DEC 25TH或-11月27日，等等..非常感謝您的幫助。 謝謝。

Answer 1

這應該為您工作：

$str = "Birthdays=>Birthday||Birthday for Girlfriend|#|Valentines Day=>Valentine Combos||Valentine Roses||Valentines Day - Feb 14th|#|Occasions=>Thinking of you";
echo $str . "<br />";
$str = preg_replace('/\s-(.*?)\|/', '|', $str);
echo $str . "<br />";

輸出：

Birthdays=>Birthday||Birthday for Girlfriend|#|Valentines Day=>Valentine Combos||Valentine Roses||Valentines Day - Feb 14th|#|Occasions=>Thinking of you
Birthdays=>Birthday||Birthday for Girlfriend|#|Valentines Day=>Valentine Combos||Valentine Roses||Valentines Day|#|Occasions=>Thinking of you

Answer 2

更新后，它將起作用：

$str = 'Birthdays=>Birthday||Birthday for Girlfriend|#|Valentines Day=>Valentine Combos||Valentine Roses||Valentines Day - Feb 14th|#|Occasions=>Thinking of you'
$a = strpos($str,'-');
$b = strpos($str, '|', $a);
if ($b) {
    $c = $b - $a;
    echo substr_replace($str, '', $a - 1, $c + 1);
}
else {
    echo strstr($str,' -', true);
}

輸出：

Birthdays=>Birthday||Birthday for Girlfriend|#|Valentines Day=>Valentine Combos||Valentine Roses||Valentines Day|#|Occasions=>Thinking of you