正則表達式將字符串分成句子

Question

我需要拆分包含句子的字符串，例如：

"this is a sentence. this is another. Rawlings, G. stated foo and bar." 

成

["this is a sentence.", "this is another.", "Rawlings, G. stated foo and bar."] 

使用正則表達式。

我發現的其他解決方案將第三句分為"Rawlings, G." 和"stated foo and bar." 這不是我想要的。

Answer 1

正則表達式通常不能解決這個問題。

你需要一個句子檢測算法， OpenNLP有一個

它很簡單，可以使用：

String sentences[] = sentenceDetector.sentDetect(yourString);

並處理了許多棘手的案件

• “Walter White Jr.有錢”
• “粉紅先生不給出提示”

Answer 2

通過嵌套的lookbehinds。

只需根據以下正則表達式拆分輸入字符串即可。 下面的正則表達式將根據剛好存在於點之后的邊界分割輸入字符串，並檢查點的前一個字符。 只有當dot的前一個字符不是一個超級字母時，它才會分裂。

String s = "this is a sentence. this is another. Rawlings, G. stated foo and bar.";
String[] tok = s.split("(?<=(?<![A-Z])\\.)");
System.out.println(Arrays.toString(tok));

輸出：

[this is a sentence.,  this is another.,  Rawlings, G. stated foo and bar.]

說明：

• (?<=(?<![AZ])\\\\.)匹配剛剛存在於dot之后的邊界，但點之前不會是大寫字母。

Answer 3

我試過這個

import java.text.BreakIterator;
import java.util.Locale;

public class StringSplit {
    public static void main(String args[]) throws Exception {
        BreakIterator iterator = BreakIterator.getSentenceInstance(Locale.US);
        String source = "This is a sentence. This is another. Rawlings, G. stated foo and bar.";
        iterator.setText(source);
        int start = iterator.first();
        for ( int end = iterator.next(); 
              end != BreakIterator.DONE; 
              start = end, end = iterator.next()) {
            System.out.println(source.substring(start, end));
        }
    }
}

out put是

This is a sentence.
This is another.
Rawlings, G. stated foo and bar.