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[英]How to parse json object and array together using volley in android
[英]How parse json object and json array together
我有兩種情況的Json輸出。 一個是找到的數據,我有一個json數組和一個json對象,如下所示:
{"data":"yes"}[{"id":"10","number":"7","text":"text7","desc":"text7_again","user_code":"0"},{"id":"11","number":"8","text":"text8","desc":"text8_again","user_code":"1"}]
其他情況是找不到數據:
{"data":"no"}
只是一個json對象。
如何在Android客戶端中解析此數據以支持兩個情景?
首先,您應該在http://jsonlint.com/中驗證您的json(如果進行測試),那么您會發現這是錯誤的json。 因此,為正確起見,在您的服務器中,您的響應應如下所示:
{"data":"yes","response":[{"id":"10","number":"7","text":"text7","desc":"text7_again","user_code":"0"},{"id":"11","number":"8","text":"text8","desc":"text8_again","user_code":"1"}]}
在這種情況下,在android中
JSONObject jsonObj = new JSONObject(response);
if (jsonObj.getString("data").compareTo("yes") == 0) {
JSONArray jsonArray = jsonObj.getJSONArray("response");
//To-Do another code
}
就這樣
這是一種可能的情況:(您需要修復json格式)
成功-
string resultJSON =
{"success":true,
"data":[
{"id":"10","number":"7","text":"text7","desc":"text7_again","user_code":"0"},
{"id":"11","number":"8","text":"text8","desc":"text8_again","user_code":"1"}]}
失敗-
string resultJSON =
{"success":false}
然后
JSONObject jsonRoot = new JSONObject(resultJSON);
bool isSuccess = jsonRoot.getBoolean("success");
if (isSuccess) {
// do the array parser
for(int i=0; i<jsonData.lenght;i++) {
JSONObject jsonObj = jsonData.getJSONObject(i);
String id = jsonObj.getString("id"); // get the value of id
String desc = jsonObj.getString("desc"); // and so on...
}
}
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