mysql如何縮短5個結果

Question

我需要從mysql取得5個計數結果，我想問一下，也許所有結果都存在縮短的代碼？ 我的代碼現在：

$result1 = mysqli_query($con,"SELECT * FROM bets WHERE status='Waiting'");
$row_cnt1 = $result1->num_rows;

$result2 = mysqli_query($con,"SELECT * FROM bets WHERE status='Win'");
$row_cnt2 = $result2->num_rows;

$result3 = mysqli_query($con,"SELECT * FROM bets WHERE status='Lost'");
$row_cnt3 = $result3->num_rows;

$result4 = mysqli_query($con,"SELECT * FROM bets WHERE status='Void'");
$row_cnt4 = $result4->num_rows;

我顯示以下代碼：

    <b>Total wins:</b> <?php echo $row_cnt1;?> <br />
<b>Total voids:</b> <?php echo $row_cnt2;?> <br />
<b>Total losts:</b> <?php echo $row_cnt3;?> <br />
<b>Total waiting:</b> <?php echo $row_cnt4;?> <br />

Answer 1

如果您像這樣進行分組，則應該能夠使用COUNT（）函數：

SELECT status, COUNT(*) AS numForStatus
FROM bets
GROUP BY status;

因此，這將顯示如下表：

|  status  | numForStatus |
+----------+--------------+
|  waiting |      5       |
|  win     |      4       |
|  lost    |      3       |
|  void    |      2       |

這是簡化查詢的一種方法，並有望使您的輸出也更容易一些。

Answer 2

$query = mysqli_query($con,"SELECT status, COUNT(*) as number FROM bets WHERE status IN ('Waiting','Win','Lost','Void') GROUP BY status");

一個查詢中將有4行2列。

注意：如果沒有狀態，則不需要WHERE語句。

您可以這樣顯示結果：

while ($row = mysqli_fetch_assoc($query)) {
    echo '<b>Total ' . $row['status'] . ': ' . $row['number'] . '</b><br/>';
}

Answer 3

試試這個代碼。 它使用SQL查詢中的GROUP BY子句和while循環來縮短代碼。

    <?php
    $qry = "SELECT COUNT(*) AS CNT, status FROM bets  GROUP by status";
    $result1 = mysqli_query($con, $qry );
    while($row = mysqli_fetch_array(result1, MYSQLI_ASSOC))
    {

    ?>
      <b>Total $row['status']:</b> <?php echo $row['CNT'];?> <br />
    <?php 
   }
   ?>