僅考慮年月日的日期差異

Question

我想只考慮年，月和日在php中計算日期差異。 現在，程序將考慮所有日期時間對象參數來計算日期差。

$DTObj = new DateTime();
$pdate = DateTime::createFromFormat("ymd", 141118);
$diff = $DTObj->diff($pdate);
$dday = $diff->format("%a");

我怎樣才能做到這一點。

Answer 1

閱讀並嘗試以下方法：

# create DateTime object with time at 00:00:00
$from = new DateTime('today'); 

# create DateTime object from ymd format
# format character ! resets all fields (year, month, ...) to the Unix Epoch and then sets the inputed date
$to = DateTime::createFromFormat('!ymd', '141118');

# calculate difference between $from and $to and return DateInterval object
$diff = $from->diff($to);

# echo difference of total number of days
echo $diff->format('%a');

演示