[英]How to execute this complex query through Laravel Eloquent?
我在SQL中有這個復雜的查詢:
SELECT distinct(albumId) as id,
band,albumName as name,
SUM(numberOfPlays) as numberOfPlays
FROM (
SELECT COUNT(*) as numberOfPlays,
tracks.album_id as albumId,
a.name as albumName,b.name as band
FROM logs l
LEFT JOIN tracks ON tracks.id=l.track_id
LEFT JOIN albums a ON tracks.album_id = a.id
LEFT JOIN bands b ON b.id = tracks.band_id
WHERE l.time>$days
GROUP by trackid
ORDER BY numberOfPlays DESC LIMIT 0,100) t
GROUP BY albumId ORDER BY numberOfPlays DESC");
到目前為止,我已經成功使用以下方法檢索了內部查詢:
Logs::select(DB::raw(
'COUNT(*) as numberOfPlays'
), 'track_id')
->where('time', '>', $days)
->orderBy('numberOfPlays', 'DESC')->take(100)
->with('track', 'track.album')
->groupBy(\DB::raw("track_id"))->orderBy('numberOfPlays', 'DESC');
如何對上述查詢返回的數據進行進一步的查詢?
實際上,您可以通過Eloquent ORM並利用返回的Collection結果上可用的方法來獲得相似的結果。 這是一個例子。 考慮到您擁有所有模型類。
$logs = Log::with(['track.album', 'track.band'])->where('time', '>', $days)->take(100)get();
class Log extends Eloquent {
public function track() {
return $this->belongsTo('Track');
}
}
Class Track extends Eloquent {
public function album() {
return $this->belongsTo('Album');
}
public function band() {
return $this->belongsTo('Band');
}
}
Class Album extends Eloquent {
}
Class Band extends Eloquent {}
現在以您想要的方式產生結果,您可以使用返回的集合將其項轉換為可表示的結構。
首先,我們將日志按專輯分組
$logsByAlbum = $logs->groupBy('track.album.id');
然后轉換分組的日志
$logsByAlbum->transform(function($album_logs) {
if(!empty($album_logs)) {
return array(
'id' => $album_logs[0]->album->id,
'album_name' => $album_logs[0]->album->name,
'numberOfPlays' => count($album_logs)
);
}
return array();
});
After transformation, we need to filter the items with empty values
$final_result = $logsByAlbum->filter(function($item) {
return !empty($item);
});
return $final_result->toArray();
這只是一個基本概念,可以幫助您使用Eloquent ORM和collection類中提供的方法的功能。
請享用! :d
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