[英]Send Data Via Post Android to PHP
因此,我正在嘗試通過Android中的Post將消息發送到PHP,這是Android Java函數:
//enviando para o backend
private void SendtoPHP(String reg) throws IOException {
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://bubbledev.com.br/gcm/getdevice.php");
try{
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
nameValuePairs.add(new BasicNameValuePair("regid", "" + reg ));
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
HttpResponse response = httpclient.execute(httppost);
}
catch (ClientProtocolException e) {
// TODO Auto-generated catch block
} catch (IOException e) {
// TODO Auto-generated catch block
}
}
PHP:
<?php
include 'conecta.php';
$device_token = urldecode($_POST['regid']);
$sql = "INSERT INTO corposa.deviceandroid"
. " (id,device_token)"
. " VALUES (NULL,'$device_token')";
mysqli_query($con,$sql);
?>
PHP很好,我已經在另一個Post上對其進行了測試並可以工作,但是當Android函數嘗試$ device_token時,不要接收任何值,並且SQL在表中保存帶有ID的“”
除了ResponseHandler之外,我使用與您的代碼相似的代碼。 這個對我有用。
HttpClient Client = new DefaultHttpClient();
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
nameValuePairs.add(new BasicNameValuePair("id", sID));
nameValuePairs.add(new BasicNameValuePair("etc", sETC));
try {
String SetServerString = "";
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://your-url.com/script.php");
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
ResponseHandler<String> responseHandler = new BasicResponseHandler();
SetServerString = httpclient.execute(httppost, responseHandler);
} catch(Exception ex) {
// failed
}
我敢肯定有更好的方法可以做到這一點,但這是我通常處理來自Android的發布請求的方式:
<?php
{
$input = json_encode(file_get_contents("php://input"));
$deviceToken = $input->regId;
mysqli_query($connection, "INSERT INTO corposa.deviceandroid (`id`, `device_token`) VALUES(NULL, '" . mysqli_real_escape_string($deviceToken) . "')";
}
另外,由於您使用的是POST而不是GET,因此傳遞到服務器的數據不是經過url編碼的,因此這里不需要urldecode。
代碼似乎還可以,只有“奇怪”的東西是:
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
因為您僅將一個BasicNameValuePair添加到列表中。 也許是問題所在...?
我在當前項目中使用了此代碼,希望它也對您有用
Map<String, String> kvPairs = new HashMap<String, String>();
kvPairs.put("regid", reg);
HttpClient httpclient = this.getNewHttpClient();
HttpPost httppost = new HttpPost("http://bubbledev.com.br/gcm/getdevice.php");
if (kvPairs != null && kvPairs.isEmpty() == false) {
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(kvPairs.size());
String k, v;
Iterator<String> itKeys = kvPairs.keySet().iterator();
while (itKeys.hasNext()) {
k = itKeys.next();
v = kvPairs.get(k);
nameValuePairs.add(new BasicNameValuePair(k, v));
}
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs, "UTF-8"));
}
HttpResponse response;
response = httpclient.execute(httppost);
String responseString = EntityUtils.toString(response.getEntity());
您的課程中也需要此方法
public static HttpClient getNewHttpClient() {
try {
KeyStore trustStore = KeyStore.getInstance(KeyStore.getDefaultType());
trustStore.load(null, null);
SSLSocketFactory sf = new RecorridoSSL(trustStore);
sf.setHostnameVerifier(SSLSocketFactory.ALLOW_ALL_HOSTNAME_VERIFIER);
HttpParams params = new BasicHttpParams();
HttpProtocolParams.setVersion(params, HttpVersion.HTTP_1_1);
HttpProtocolParams.setContentCharset(params, HTTP.UTF_8);
SchemeRegistry registry = new SchemeRegistry();
registry.register(new Scheme("http", PlainSocketFactory.getSocketFactory(), 80));
registry.register(new Scheme("https", sf, 443));
ClientConnectionManager ccm = new ThreadSafeClientConnManager(params, registry);
return new DefaultHttpClient(ccm, params);
} catch (Exception e) {
return new DefaultHttpClient();
}
}
希望我不要忘記任何事情,以其他方式告訴我
伙計們,錯誤是我的PHP
$device_token = urldecode($_POST['regid']);
這個urldecode弄亂了我的代碼哈哈
感謝所有幫助
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