[英]grep word in text files using perl
我的文件夾中有一個文本文件A00010.txt A00011.txt A00012.txt到A00099.txt,其中包含不同的條目,例如,
umxwtdn8vtnt_n
umxwtdtnt_nn8v
umxwt_ntdn8vtn
u8vtnt_nmxwtdn
utnt_nmxwtdn8v
我的Perl代碼是
#!/usr/bin/perl
use strict;
my $count = 10;
for ($count = 10; $count<= 99; $count++) {
my $result = `/bin/cat /myfolder/A000$count.txt | grep "umxwtdn8vtnt_n"`;
return $result;
}
print $result;
我試圖獲得$ result值,但顯示為空
/myfolder
確實在根目錄中嗎? (在ls /
看到了什么?在myfolder
看到了嗎?)在Unix系統的根目錄中添加內容非常罕見,而且我不認為您會弄亂/
。
另外,您將在子例程( sub { }
)之外返回$result
,如果是這種情況,應該會遇到Perl運行時錯誤。
如果要復制代碼片段,請注意$result
是局部變量,在子例程結束后它會消失。
您真的需要使用Perl嗎?
如果不:
find /myfolder -name "A000??.txt" | xargs grep -n "umxwtdn8vtnt_n"
會在文件中找到模式並告訴您在哪一行...
您想知道該模式是否在您的一個或多個文件中? 然后:
my $not_found = 1;
for (my $count = 10; $count<= 99; $count++) {
my $result = `grep "umxwtdn8vtnt_n" /myfolder/A000$count.txt`;
if ($result) {
print $result;
$not_found = 0; # error level 0 = no error = found
last;
}
}
exit $not_found; # error level 1 = error = not found
仍在嘗試了解您的需求...
my $result;
for (my $count = 10; $count<= 99; $count++) {
# you should test that A000$count.txt actually exists here
my $match = `grep "umxwtdn8vtnt_n" /myfolder/A000$count.txt`;
if ($match == "umxwtdn8vtnt_n") {
print "found $match in A000${count}.txt";
$result = $match;
last; # exit for loop
}
}
if ($result) {
# do something with it?
}
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