簡體   English   中英

GWT處理StatusCodeException

[英]GWT Handling StatusCodeException

如果我的服務方法拋出新的MyException(“ Some原因”),如何從服務器端獲取異常; 我想在onFailure方法中獲取MyException,但實際上我得到了StatusCodeException。 我可以獲取MyException以便在UI上顯示錯誤消息嗎:Window.alert(exception.getMessage()); ->印刷品:“某些原因”

@RemoteServiceRelativePath("reportService.rpc")
public interface ReportService extends RemoteService {
    void saveReport(ReportDTO reportDTO) throws MyException;
}

 @Override
    public void saveReport(ReportDTO reportDTO) throws MyException {
        //Report report = ReportFunc.INST.apply(reportDTO);
        //reportRepository.save(report);
        throw new MyException("Some reason");
    }

 reportServiceAsync.saveReport(reportDTO, new AsyncCallback<Void>() {
                    @Override
                    public void onSuccess(Void result) {
                        Window.alert("Successfully saved");
                    }

                    @Override
                    public void onFailure(Throwable e) {
                        Window.alert(e.getMessage());
                    }
                });

class MyException extends RuntimeException implements Serializable{
  ....
}

您的異常應擴展Exception,而不是RuntimeException。

暫無
暫無

聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.

 
粵ICP備18138465號  © 2020-2024 STACKOOM.COM