[英]String.replaceAll() not working in my looop
因此,我試圖刪除電話號碼中的所有特殊字符以僅保留數字,但不幸的是,它不起作用。 我查找了其他解決方案,但它們仍然無法正常工作。 即使在調試器中運行它之后,.replaceAll()方法似乎也無濟於事。 這是我的代碼如下:
if (c !=null) {
//populate database with first 100 texts of each contact
dbs.open();
//comparator address, count to 100
String addressX = "";
int count = 0;
c.moveToFirst();
for (int i = 0; i < c.getCount(); i++) {
//get c address
String addressY = c.getString(c.getColumnIndex("address"));
addressY.replaceAll("[^0-9]+", "").trim();
//one for the address, other to be able to sort threads by date !Find better solution!
if (!smsAddressList.contains(addressY)) {
//custom object so listview can be sorted by date desc
String date = c.getString(c.getColumnIndex("date"));
smsDateList.add(date);
smsAddressList.add(addressY);
}
//less than 100 texts, add to database, update comparator, add to count
if (count < 100) {
c.moveToPosition(i);
addText(c);
addressX = addressY;
count++;
}
//if more 100 texts, check to see if new address yet
else if (count>100) {
//if still same address, just add count for the hell of it
if (addressX.equals(addressY)) {
count++;
}
//if new address, add text, reset count
else {
addText(c);
addressX = addressY;
count = 1;
}
}
}
}
String.replaceAll()
返回修改后的字符串,它不會就地修改字符串。 因此,您需要類似:
addressY = addressY.replaceAll("[^0-9]+", "").trim();
我也很確定這里的trim
是多余的,因為您已經使用replaceAll
去除了空白。 因此,您可以擺脫:
addressY = addressY.replaceAll("[^0-9]+", "");
字符串是不可變的。 replaceAll
僅返回具有所需修改的新String。
您需要做:
addressY = addressY.replaceAll("[^0-9]+", "").trim();
addressY = addressY.replaceAll("[^0-9]+", "").trim();
replaceAll
方法創建一個新的String,因此您需要重新聲明該變量。
確保將更改后的字符串分配給addressY
addressY = addressY.replaceAll("[^0-9]+", "").trim();
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