SQL - 匹配兩行的條件

Question

我試圖從SQL開發人員中提取匹配兩行條件的數據。 這兩行都有一個唯一值（ID），表名是abc.tcd

ID  =  Type =   GL code = amount
1   =   Debit =  0701  =  10000
1  =    credit = 0601 =   10000
1  =    Credit=  0501  =  1000
1   =   Debit=   0401   = 1000
2   =   Debit =  0701  =  9000
2   =   credit = 0801  =  9000
3   =   Debit  = 0701  =  6000
3   =   credit = 0601  =  6000

條件1：

GL code = '0701'   having Type = 'Debit' 

條件2：

GL code = '0601'   having Type = 'Credit' 

預期產量：

ID    Type    GL code  amount

1  =    Debit  = 0701 =   10000
1  =    credit = 0601 =   10000
1  =    Credit = 0501 =   1000
1  =    Debit  = 0401 =   1000
3  =    Debit  = 0701 =   6000
3  =    credit = 0601 =   6000

輸出應顯示基於ID所有行

Answer 1

如果我正確理解了這個問題，你想要提取某些ID的所有行，其中兩個不同的行滿足兩個不同的條件。 你可以使用一對夫婦in運營商：

SELECT *
FROM   mytable
WHERE  id IN (SELECT id
              FROM   my_table
              WHERE  GLCode = '0701' AND Type = 'Debit')
        AND id IN (SELECT id
                   FROM   my_table
                   WHERE  GLCode = '0601' AND Type = 'Credit')

當然，這可以很容易地轉換為使用exists運算符：

SELECT *
FROM   mytable a
WHERE  EXISTS (SELECT *
               FROM   my_table b
               WHERE  a.id = b.id AND b.GLCode = '0701' AND b.Type = 'Debit')
        AND EXISTS (SELECT *
                    FROM   my_table c
                    WHERE  a.id = c.id AND c.GLCode = '0601' AND c.Type = 'Credit')

更優雅的方式可能是將單個查詢中的所有條件與s or s一起count並count其中有多少條件得到滿足：

SELECT *
FROM   mytable
WHERE  id IN (SELECT   id
              FROM     my_table
              WHERE    (GLCode = '0701' AND Type = 'Debit') OR
                       (GLCode = '0601' AND Type = 'Credit')
              GROUP BY id
              HAVING   COUNT(*) = 2)

Answer 2

另一種選擇：

SELECT * FROM MyTable
INNER JOIN
(
  SELECT ID
  FROM MyTable
  WHERE (GLCode = '0701' AND Type = 'Debit') OR (GLCode = '0601' AND Type = 'Credit')
  GROUP BY ID
  HAVING COUNT(DISTINCT GLCode) = 2 AND COUNT(DISTINCT Type) = 2
) X
ON MyTable.ID = x.ID;

SqlFiddle在這里

基本上“找到具有符合標准的兩個不同行的ID”。 然后，我們返回具有此ID的所有行

編輯

您的真實查詢將如下所示：

SELECT *
FROM tbaadm.ctd 
INNER JOIN
(SELECT Tran_id 
    FROM tbaadm.ctd 
    WHERE ((GL_SUB_HEAD_CODE = '06106' AND PART_TRAN_TYPE = 'C') 
          OR (GL_SUB_HEAD_CODE = '29101' AND PART_TRAN_TYPE = 'D'))
       AND (tran_date >= '01-12-2014' AND tran_date < '30-12-2014')
    GROUP BY Tran_id
    HAVING COUNT(DISTINCT GL_SUB_HEAD_CODE) = 2 AND COUNT(DISTINCT PART_TRAN_TYPE) = 2
) X
ON tbaadm.ctd = x.Tran_id;

由於運算符優先級，ANDs周圍的括號顯然是多余的，但可能有助於提高可讀性？

另外，請注意日期范圍檢查是否包含開始日期但排除結束日期，即x >= start and x < end