[英]PHP - Getting the filepath of the file after uploading to server
美好的一天。 我正在將圖像文件上傳到我的PHP服務器。 我已成功將文件上傳到文件夾。 我現在想做的是,在組裝JSON響應時,我想獲取文件的新文件路徑,這樣我就可以知道它在程序上的位置。
到目前為止,這是我的PHP代碼:
<?php
header('Content-Type: text/html; charset=utf-8');
if (
!isset($_FILES['fileToUpload']['error']) ||
is_array($_FILES['fileToUpload']['error'])
) {
die(json_encode(array(
'success' => false,
'status' => "Invalid Parameters. - 1",
'files' => $_FILES
)));
}
// Check $_FILES['fileToUpload']['error'] value.
switch ($_FILES['fileToUpload']['error']) {
case UPLOAD_ERR_OK:
break;
case UPLOAD_ERR_NO_FILE:
die(json_encode(array(
'success' => false,
'status' => "No file sent. - 2",
'files' => $_FILES
)));
case UPLOAD_ERR_INI_SIZE:
case UPLOAD_ERR_FORM_SIZE:
die(json_encode(array(
'success' => false,
'status' => "Exceeded filesize limit. - 3",
'files' => $_FILES
)));
default:
die(json_encode(array(
'success' => false,
'status' => "Unknown errors. - 4",
'files' => $_FILES
)));
}
// You should also check filesize here.
if ($_FILES['fileToUpload']['size'] > 1000000) {
die(json_encode(array(
'success' => false,
'status' => "Exceeded File Size Limit. - 5",
'files' => $_FILES
)));
}
// DO NOT TRUST $_FILES['fileToUpload']['mime'] VALUE !!
// Check MIME Type by yourself.
$finfo = new finfo(FILEINFO_MIME_TYPE);
if (false === $ext = array_search(
$finfo->file($_FILES['fileToUpload']['tmp_name']),
array(
'jpg' => 'image/jpeg',
'png' => 'image/png',
'gif' => 'image/gif',
),
true
)) {
die(json_encode(array(
'success' => false,
'status' => "Invalid file format. - 6",
'files' => $_FILES
)));
}
// You should name it uniquely.
// DO NOT USE $_FILES['fileToUpload']['name'] WITHOUT ANY VALIDATION !!
// On this example, obtain safe unique name from its binary data.
if (!move_uploaded_file(
$_FILES['fileToUpload']['tmp_name'],
sprintf('./gallery/%s.%s',
sha1_file($_FILES['fileToUpload']['tmp_name']),
$ext
)
)) {
die(json_encode(array(
'success' => false,
'status' => "Failed to move uploaded file. - 7",
'files' => $_FILES
)));
}
$filePathFull = sprintf('./gallery/%s.%s',
sha1_file($_FILES['fileToUpload']['tmp_name']);
$uploaddir = '/gallery/';
$uploadfile = $uploaddir . basename($_FILES['fileToUpload']['tmp_name']);
die(json_encode(array(
'success' => true,
'status' => "File is uploaded successfully. - 8",
'files' => $_FILES,
'filePath' => $uploadfile
)));
?>
我正在嘗試獲取新的文件路徑,即/gallery/
+文件名,但是,在ExtJS部分中處理它時,我得到的是無效的JSON對象。
誰能幫我解決我的問題? 我也嘗試了sprintf('./gallery/%s.%s', sha1_file($_FILES['fileToUpload']['tmp_name']);
但這似乎不起作用。
很感謝任何形式的幫助。
編輯:
到目前為止,這有效:
$uploaddir = '/gallery/';
$uploadFile = $uploaddir . basename($_FILES['fileToUpload']['tmp_name']);
die(json_encode(array(
'success' => true,
'status' => "File is uploaded successfully. - 8",
'filePath' => $uploadFile
)));
但是,我沒有文件擴展名,但是卻得到類似: /gallery/phptnLZJm
但是經過檢查,實際上已上傳圖像,但文件名已關閉。
我成功了 我認為這是sha1_file
的問題。 現在的代碼是:
if (!move_uploaded_file(
$_FILES['fileToUpload']['tmp_name'],
sprintf('./gallery/%s.%s',
basename($_FILES['fileToUpload']['tmp_name']),
$ext
)
)) {
die(json_encode(array(
'success' => false,
'status' => "Failed to move uploaded file. - 7",
'files' => $_FILES
)));
}
// $uploadFile = sprintf('./gallery/%s.%s',
// sha1_file($_FILES['fileToUpload']['tmp_name']);
$uploaddir = '/gallery/';
// $uploadFile = $uploaddir . basename($_FILES['fileToUpload']['tmp_name']);
$name = $_FILES["fileToUpload"]["tmp_name"];
$fullPath = sprintf('/gallery/%s.%s',
basename($_FILES['fileToUpload']['tmp_name']),
$ext
);
die(json_encode(array(
'success' => true,
'status' => "File is uploaded successfully. - 8",
'filePath' => "$fullPath"
)));
以前,在組裝$fullPath
時,我將稱呼sha1_file
而不是basename
,我也不知道為什么。 是因為它已經被移動並且現在有了另一個名稱了嗎?
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