[英]Replace word for blank using sed
我有一個包含所有用戶的mysql授權的文件。 看起來像這樣:
GRANT USAGE ON *.* TO 'web_user'@'10.16.%' IDENTIFIED BY PASSWORD '*288A8C32D8C898U779EDA321A6CD6525DB2D3166';
GRANT SELECT, INSERT, UPDATE, DELETE, EXECUTE ON `users`.* TO 'web_user'@'10.16.%';
GRANT SELECT, INSERT, UPDATE, DELETE ON `zip`.* TO 'web_user'@'10.16.%';
GRANT USAGE ON *.* TO 'alarms'@'10.16.%' IDENTIFIED BY PASSWORD '*E8DEF50F129E0DAF1113382944F603677BA11260';
GRANT SELECT, EXECUTE ON `users`.* TO 'alarms'@'10.16.%';
...
...
...
使用sed我需要刪除密碼。 我應該看起來像這樣:
GRANT USAGE ON *.* TO 'web_user'@'10.16.%' IDENTIFIED BY PASSWORD
GRANT SELECT, INSERT, UPDATE, DELETE, EXECUTE ON `users`.* TO 'web_user'@'10.16.%';
GRANT SELECT, INSERT, UPDATE, DELETE ON `zip`.* TO 'web_user'@'10.16.%';
GRANT USAGE ON *.* TO 'alarms'@'10.16.%' IDENTIFIED BY PASSWORD
GRANT SELECT, EXECUTE ON `users`.* TO 'alarms'@'10.16.%';
...
...
...
sed 's/identified by password.*/identified by password/i'
這應該適合你:
sed 's/\(PASSWORD\).*$/\1/' file
如果您想要對此file
進行更改,只需為您的sed
添加-i
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