PHP如何從檢查數組中多個日期范圍的函數中獲取值

Question

我有一個檢查今天的日期是否在數組中多個日期間隔之間的函數。 我唯一需要的是此函數在checkRange函數中返回$ location值。

function promoDates(){
    $current = strtotime("now");

    // Array gives a place, start date, and end date
    $intervals = array(
        //The $current start time falls between the dates in washington array
        array('washington', strtotime("2015-01-08 00:00"), strtotime("2015-01-30 00:00")),
        array('california', strtotime("2015-06-02 00:00"), strtotime("2015-06-17 00:00")),
        array('texas', strtotime("2015-02-12 00:00"), strtotime("2015-02-27 00:00")),
        array('ney-york', strtotime("2015-05-12 00:00"), strtotime("2015-05-26 00:00")),
        array('tennessee', strtotime("2015-10-29 00:00"), strtotime("2015-11-12 00:00")),
        array('utah', strtotime("2015-09-15 00:00"), strtotime("2015-09-30 00:00")),
        array('florida', strtotime("2015-11-12 00:01"), strtotime("2015-11-27 00:00"))
    );

    function checkRange($location, $startDate, $endDate, $currentDate){
        if ($currentDate >= $startDate && $currentDate <= $endDate){
            // Successfully echos 'washington' to page
            echo $location."<br>";
            return $location;
        }
    }

    for ($i = 0; $i <= 6; $i++){
        checkRange($intervals[$i][0], $intervals[$i][1], $intervals[$i][2], $current);
    }
    //This does not echo the location from the checkRange function
    echo checkRange();
}

我只需要獲取promoDates函數來返回checkRange函數正在回顯的內容的幫助。 有什么方法可以在checkRange函數中設置變量並將其返回到promoDates函數中嗎？

Answer 1

好吧，您沒有將任何參數傳遞給checkRange()函數...我也將更改checkRange函數的簽名，以獲取一個間隔數組：

function promoDates() {

    $current = strtotime("now");

    // Array gives a place, start date, and end date
    $intervals = array(
        //The $current start time falls between the dates in washington array
        array('washington', strtotime("2015-01-08 00:00"), strtotime("2015-01-30 00:00")),
        array('california', strtotime("2015-06-02 00:00"), strtotime("2015-06-17 00:00")),
        array('texas', strtotime("2015-02-12 00:00"), strtotime("2015-02-27 00:00")),
        array('ney-york', strtotime("2015-05-12 00:00"), strtotime("2015-05-26 00:00")),
        array('tennessee', strtotime("2015-10-29 00:00"), strtotime("2015-11-12 00:00")),
        array('utah', strtotime("2015-09-15 00:00"), strtotime("2015-09-30 00:00")),
        array('florida', strtotime("2015-11-12 00:01"), strtotime("2015-11-27 00:00"))
    );

    // we will use this like a filter
    function checkRange($currentDate, $promo) {
        list($location, $startDate, $endDate) = $promo;
       // return true or false
      return (($currentDate >= $startDate) && ($currentDate <= $endDate));
    }

    // loop over the intervals until we find a match then return it:
    foreach($intervals as $promoData) {
       if (checkRange($current, $promoData) === true) {
          return $promoData[0];
       }
    }

    // return null if we do not find any
    return null;     
}

用法如下所示：

echo promoDates();

Answer 2

編輯：實際上，我只是按照@prodigitalson的建議進行了修復，並檢查每個循環迭代是對還是錯，然后將值返回為真。

function checkRange($startDate, $endDate, $currentDate, $loc){
    if ($currentDate >= $startDate && $currentDate <= $endDate){
        return true;
    } else{
        return null;
    }
}

for ($i = 0; $i <= 6; $i++){
    if(checkRange($intervals[$i][1], $intervals[$i][2], $current, $intervals[$i][0]) == true){
        return $intervals[$i][0];
    }
}

並刪除echo echoRange（）; 在底部。