[英]Syntax ERROR inside MySQL TRIGGER -> Insert Into Statement
我有一個觸發器,它將新行插入到另一個表中,但是在某處出現錯誤,因為它告訴我我的值是NULL,並且它們不是或至少不應該是。
觸發代碼
分隔符//
CREATE TRIGGER new_active_user AFTER UPDATE ON `pre_reg`
FOR EACH ROW
BEGIN
DECLARE currentUser INT;
DECLARE banned INT;
DECLARE user_type INT;
DECLARE username VARCHAR (25);
DECLARE password VARCHAR (60);
DECLARE usersince datetime;
DECLARE email varchar(40);
SET @currentUser := (select `id` FROM `pre_reg` WHERE `active` = 1);
SET @banned = 0;
SET @user_type = 3;
SET @username := (select `username` FROM `pre_reg` WHERE `id` = currentUser);
SET @password := (select `password` FROM `pre_reg` WHERE `id` = currentUser);
SET @usersince := (select `date` FROM `pre_reg` WHERE `id` = currentUser);
SET @email := (select `email` FROM `pre_reg` WHERE `id` = currentUser);
INSERT INTO `users` (`id`, `username`, `password`) VALUES (@currentUser, @username, @password);
END//
Delimiter ;
我什至嘗試在SET用戶名,密碼,電子郵件SET語句中使用currentUser的值進行硬編碼。 但是,它不起作用,我得到以下錯誤:
錯誤
SQLSTATE [23000]:違反完整性約束:1048列“用戶名”不能為空
我什至嘗試僅輸入ID(@currentUser)以確保其設置,其余的都進行了硬編碼(工作正常!所以我假設SET語句中存在錯誤,但無法弄清楚它告訴我的總是值是空值
這就是我創建表格的方式
CREATE TABLE `pre_reg` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`username` varchar(25) NOT NULL,
`password` varchar(60) NOT NULL,
`email` varchar(40) NOT NULL,
`authentication` varchar(32) NOT NULL,
`active` smallint(1) NOT NULL DEFAULT '0',
`date` datetime NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (`id`),
UNIQUE KEY `username` (`username`,`email`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1
GO
CREATE TABLE `users` (
`id` INT PRIMARY KEY,
`username` VARCHAR (25) NOT NULL,
`password` VARCHAR (60) NOT NULL,
`banned` SMALLINT NOT NULL DEFAULT 0,
`user_since` datetime NOT NULL DEFAULT CURRENT_TIMESTAMP
)ENGINE=InnoDB DEFAULT CHARSET=latin1
GO
這可能是您想要的:
Delimiter //
CREATE TRIGGER new_active_user AFTER UPDATE ON `pre_reg`
FOR EACH ROW
BEGIN
INSERT INTO `users` (`id`, `username`, `password`)
VALUES (new.id, new.username, new.password);
END//
Delimiter ;
它將pre_reg
剛剛更新的內容插入到users
表中。
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