[英]How to check values in collection for uniques by some criteria using Java 8
我有以下課程:
public final class InfoWrapper {
private int count;
private int itemCode;
private String name;
public InfoWrapper() {
}
public InfoWrapper(final int count, final int itemCode, final String name) {
super();
this.count = count;
this.itemCode = itemCode;
this.name = name;
}
public int getCount() {
return count;
}
public int getItemCode() {
return itemCode;
}
public String getName() {
return name;
}
}
這是我的測試課:
public class TestClass {
public static void main(String [] args) {
Deque<InfoWrapper> list = new ArrayDeque<InfoWrapper>();
list.add(new InfoWrapper(3, 111, "aaa"));
list.add(new InfoWrapper(7, 112, "bbb"));
list.add(new InfoWrapper(12, 113, "ccc"));
list.add(new InfoWrapper(6, 113, "ccc"));
list.add(new InfoWrapper(8, 113, "ccc"));
list.add(new InfoWrapper(3, 113, "ccc"));
System.out.println("Is good enought : " + isGoodEnought(list, 3));
}
private static boolean isGoodEnought(final Deque<InfoWrapper> list, final int maxFailsCount) {
return !list.stream().limit(maxFailsCount).skip(1).anyMatch((res) -> res.getName().equals("ccc"));
}
}
我的方法isGoodEnough()檢查前3個元素的名稱是否等於“ ccc”,但實際上我需要檢查名稱是否唯一。
private static boolean isGoodEnought(Deque<InfoWrapper> list,
int maxFailsCount) {
return list.stream()
.limit(maxFailsCount)
.map(InfoWrapper::getName)
.distinct()
.count() == maxFailsCount;
}
請注意,即使前兩個名稱相同,也會遍歷maxFailsCount
個元素。 如果maxFailsCount
可以是一個較大的值,則可能需要使用類似
private static boolean isGoodEnought(Deque<InfoWrapper> list, int max) {
Set<String> seenNames = new HashSet<>();
for (Iterator<InfoWrapper> i = list.iterator(); i.hasNext() && max-- > 0;)
if (!seenNames.add(i.next().getName()))
return false;
return true;
}
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