[英]C - Concatenate 2 arrays in one using for loop
我想用C語言運行一個For Loop進行連接,然后將結果復制到新數組中。
// Simple array with numbers to be appended at the end of the array "type" below
char numbers[20][2]={"0","1","2","3","4","5","6","7","8","9","10","11","12","13","14","15","16","17","18","19"};
//after each of these words i want to append the number found above.
char type[10][30]={"rizi","makaronia","kafes","giaourti","feta","avga","sampuan","rouxa","aporipantiko","aposmitiko"};
//This is the array i wish to add the results. This way i will create 20 of each type
char random_type [20][30];
int i,j;
for(i = 0; i < 10; i++)
{
for (j = 0; i < 20; j++)
{
strcpy(random_type[i][j],type[j]);
}
}
可以進行一些簡化,例如不需要連續編號的數組。 有一些錯誤,例如@iharob和@Jasper指出,OP使用strcpy()
寫入二維char數組的每個char,它實際上是一維字符串數組。
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#define WORDS 10
#define ANSWERS 20
#define NUMBERS 20
int main()
{
// Words to have a number appended
char type[WORDS][30]={"rizi","makaronia","kafes","giaourti","feta",
"avga","sampuan","rouxa","aporipantiko","aposmitiko"};
//This is the array to create the results.
char random_type [ANSWERS][35];
int i, word, numb;
srand ((unsigned)time(NULL));
for(i=0; i<ANSWERS; i++) {
numb = rand() % NUMBERS;
word = rand() % WORDS;
sprintf(random_type[i], "%s %d", type[word], numb);
}
for(i=0; i<ANSWERS; i++) {
printf ("%s\n", random_type[i]);
}
return 0;
}
程序輸出:
aporipantiko 19
makaronia 14
makaronia 9
aposmitiko 10
sampuan 6
feta 10
feta 2
giaourti 3
rizi 10
feta 8
sampuan 7
rouxa 4
rizi 8
giaourti 0
giaourti 19
aposmitiko 13
rouxa 2
avga 13
giaourti 13
aporipantiko 8
雖然,也許OP意味着用每個數字替換每個單詞,但在這種情況下,我提供了這個。
#include <stdio.h>
#include <stdlib.h>
#define WORDS 10
#define NUMBERS 20
int main()
{
// Words to have a number appended
char type[WORDS][30]={"rizi","makaronia","kafes","giaourti","feta",
"avga","sampuan","rouxa","aporipantiko","aposmitiko"};
//This is the array to create the results.
char random_type [WORDS][NUMBERS][35];
int i, j;
for(i=0; i<WORDS; i++)
for(j=0; j<NUMBERS; j++)
sprintf(random_type[i][j], "%s %d", type[i], j);
for(i=0; i<WORDS; i++)
for(j=0; j<NUMBERS; j++)
printf ("%s\n", random_type[i][j]);
return 0;
}
在OP注釋之后,第三個解決方案創建了600個字符串的數組。
#include <stdio.h>
#include <stdlib.h>
#define WORDS 10
#define NUMBERS 20
int main()
{
// Words to have a number appended
char type[WORDS][30]={"rizi","makaronia","kafes","giaourti","feta",
"avga","sampuan","rouxa","aporipantiko","aposmitiko"};
//This is the array to create the results.
char random_type [WORDS*NUMBERS][35];
int i, j, k=0;
for(i=0; i<WORDS; i++)
for(j=0; j<NUMBERS; j++)
sprintf(random_type[k++], "%s %d", type[i], j);
for(k=0; k<WORDS*NUMBERS; k++)
printf ("%s\n", random_type[k]);
return 0;
}
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