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無法從字符串構造類型為java.lang.Class的Map鍵:無法將鍵解析為Class

[英]Can not construct Map key of type java.lang.Class from String: unable to parse key as Class

我在反序列化包含以Class為鍵的map的對象時遇到問題:

public class TestSerializeMap {

    public static class TestClass {
        private Map<Class<? extends Object>, String> map = new HashMap<>();

        public TestClass() {
        }

        public Map<Class<? extends Object>, String> getMap() {
            return map;
        }
    }

    @Test
    public void testPropertyMapWithClassAsKey() throws Exception {
        TestClass testClass = new TestClass();
        testClass.getMap().put(ArrayList.class, "ArrayList");
        testClass.getMap().put(HashMap.class, "HashMap");

        ObjectMapper mapper = new ObjectMapper();

        String json = mapper.writerWithDefaultPrettyPrinter().writeValueAsString(testClass);
        System.out.println(json);
        mapper.readValue(json, TestClass.class);
    }
}

引發此異常:

com.fasterxml.jackson.databind.exc.InvalidFormatException: Can not construct     Map key of type java.lang.Class from String "class java.util.ArrayList": not a valid representation: Can not construct Map key of type java.lang.Class from String "class java.util.ArrayList": unable to parse key as Class
 at [Source: {
  "map" : {
    "class java.util.ArrayList" : "ArrayList",
    "class java.util.HashMap" : "HashMap"
  }
}; line: 3, column: 5]
 at [Source: {
  "map" : {
    "class java.util.ArrayList" : "ArrayList",
    "class java.util.HashMap" : "HashMap"
  }
}; line: 3, column: 5] (through reference chain: org.test.TestClass["map"])
    at com.fasterxml.jackson.databind.exc.InvalidFormatException.from(InvalidFormatException.java:55)
    at com.fasterxml.jackson.databind.DeserializationContext.weirdKeyException(DeserializationContext.java:913)
    at com.fasterxml.jackson.databind.deser.std.StdKeyDeserializer.deserializeKey(StdKeyDeserializer.java:131)
    at com.fasterxml.jackson.databind.deser.std.MapDeserializer._readAndBind(MapDeserializer.java:404)
    at com.fasterxml.jackson.databind.deser.std.MapDeserializer.deserialize(MapDeserializer.java:333)
    at com.fasterxml.jackson.databind.deser.std.MapDeserializer.deserialize(MapDeserializer.java:25)
    ...

當我嘗試直接序列化地圖時:

@Test
public void testMapWithClassAsKey() throws Exception {
    Map<Class<? extends Object>, String> map = new HashMap<>();
    map.put(ArrayList.class, "ArrayList");
    map.put(HashMap.class, "HashMap");

    ObjectMapper mapper = new ObjectMapper();

    String json = mapper.writerWithDefaultPrettyPrinter().writeValueAsString(map);
    System.out.println(json);
    mapper.readValue(json, Map.class);
}

然后它可以正常工作。 我的第一次考試中缺少什么?

編輯:

發現第二項測試不正確。 它應該是:

@Test
public void testMapWithClassAsKey() throws Exception {
    Map<Class<? extends Object>, String> map = new HashMap<>();
    map.put(ArrayList.class, "ArrayList");
    map.put(HashMap.class, "HashMap");

    ObjectMapper mapper = new ObjectMapper();

    String json = mapper.writerWithDefaultPrettyPrinter().writeValueAsString(map);
    System.out.println(json);
    mapper.readValue(json, new TypeReference<Map<Class<? extends Object>, String>>(){});
}

現在,它以與第一個相同的異常失敗。

我在github上提交了一個發現。 FasterXML的Tatu對此進行了調查並解決了該問題。 問題是map中Class<?>鍵的序列化。

它應該在傑克遜數據綁定版本2.5.1中修復

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