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如何使用正則表達式搜索來搜索變量值

[英]How to use regex search to search a variable value

我有多行,我只需要選擇那些包含特定值的行。 例如,

[DEBUG] 2014-12-01 16:39:12,049 [1984] Agent Logger Initialized
[DEBUG] 2014-12-01 16:39:12,049 [2884] Agent Logger Initialized
[DEBUG] 2014-12-01 16:39:12,049 [2884] Agent Actuation Logger Initialized

所以我有一個變量為var = 1984。

id=re.search(r'\[var\],s,re.I|re.M|re.S)
if id:
   print line

上面的正則表達式只能搜索var = 1984,並且應該打印包含該值“ [1984]”的行。有人可以建議如何做嗎?我需要在Linux中搜索,我正在使用Python 2.6。

這個正則表達式應該工作:

var=1984
reg = '.+'+str(var)+'.+'
id=re.search(reg,s,re.I|re.M|re.S)

或簡單地說:

import re

s = ['[DEBUG] 2014-12-01 16:39:12,049 [1984] Agent Logger Initialized',
     '[DEBUG] 2014-12-01 16:39:12,049 [2884] Agent Logger Initialized',
     '[DEBUG] 2014-12-01 16:39:12,049 [2884] Agent Actuation Logger Initialized']

var = 1984
for line in s:
    id = re.findall(r'.+%d.+' % var, line, re.I | re.M | re.S)
    if id:
        print line

輸出:

[DEBUG] 2014-12-01 16:39:12,049 [1984] Agent Logger Initialized

您也可以使用簡單的if條件進行操作:

from io import StringIO

text = StringIO(u"""\
[DEBUG] 2014-12-01 16:39:12,049 [1984] Agent Logger Initialized
[DEBUG] 2014-12-01 16:39:12,049 [2884] Agent Logger Initialized
[DEBUG] 2014-12-01 16:39:12,049 [2884] Agent Actuation Logger Initialized
""")

for line in text:
    if '[1984]' in line:
        print line

[DEBUG] 2014-12-01 16:39:12,049 [1984] Agent Logger Initialized

這應該工作:

#!/usr/bin/env python
# -*- coding: utf-8 -*-

import re
var = '\[1984\]'
with open("test.log")  as fp: # assuming your log file is test.log
    lines = fp.readlines()
    for line in lines:
        line = line.strip()
        if re.match(r'.*'+str(var)+'.*',line): # may be you want to add some more strict matching rules here.
            print line

# vim:ai:et:sts=4:sw=4:

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