為什么我的字符串比較在第一次測試中失敗？

Question

如果我輸入h或l，c它會不斷提示我輸入數字，而不是輸入正確的大小寫。

print("Please think of a number between 0 and 100! "); 

low = 0;
high = 100
mid = 50

while True:
    print("Is your secret number " + str(mid) + "?")
    guess = raw_input("Enter 'h' to indicate the guess is too high. Enter 'l' to indicate the guess is too low. Enter 'c' to indicate I guessed correctly.")

    if (guess != "h") or (guess != "l") or (guess != "c"):
         print "Sorry, I did not understand your input."   
         print "Is your secret number %i?" % mid
         guess = raw_input("Enter 'h' to indicate the guess is too high. Enter 'l' to indicate the guess is too low. Enter 'c' to indicate I guessed correctly.")
    elif  guess == 'l':
         low = mid
    elif  guess == 'h':
         high = mid
    else:
         print "Game over. Your secret number was: %c" % mid 
         break          
    mid = (high + low) / 2 

Answer 1

您的condn exp錯誤，應該是

if (guess != "h") and (guess != "l") and (guess != "c"):

這意味着如果該值不是h且l和c則執行。 您的陳述反而暗示如果輸入不是h或l或c則執行。 因此，當您將h作為輸入時，它會失敗，因為它不是l和c

或者，如評論中所述 ，您可以改為，

if guess not in ['h', 'l', 'c']: