[英]How to concatenate two columns with joined table in mysql
我有兩個表issue_details
和payees
,如下所示,帶有值:
表格: issue_details
+----------+------------+----------+----------+
| check_no | issue_date | payee_id | lddap_no |
+----------+------------+----------+----------+
| 0 | 2015-01-01 | | 11101-15 |
| 1 | 2015-01-24 | | 11101-15 |
| 34561 | 2015-01-24 | 10 | |
| 34562 | 2015-01-24 | 13 | |
+----------+------------+----------+----------+
表: 收款人
+----------+--------------------+
| payee_id | payee_name |
+----------+--------------------+
| 1 | John Smith |
| 10 | Chen Lou |
| 11 | Mark Dello |
| 12 | ANTRECCO |
| 13 | Shay Ridz |
+----------+--------------------+
我執行此查詢以連接兩個表,以在我的issue_details
表中描述收款人姓名。
SELECT
issue_details.issue_date AS date,
issue_details.check_no AS check_no,
payees.payee_name AS payee
FROM
issue_details
INNER JOIN
payees ON issue_details.payee_id = payees.payee_id
結果 :
+----------+------------+----------+
| check_no | issue_date | payee |
+----------+------------+----------+
| 34561 | 2015-01-24 | Chen Lou |
| 34562 | 2015-01-24 | Shay Ridz|
+----------+------------+----------+
如果我這樣做:
SELECT
issue_details.issue_date AS date,
issue_details.check_no AS check_no,
CONCAT(payees.payee_name, '', lddap_no) AS payee
FROM
issue_details
INNER JOIN
payees ON issue_details.payee_id = payees.payee_id
結果仍然與上面相同。 它不將payee_name
(從表payees連接)的兩列和payee_name
連接lddap_no
。
這是我想發生的事情:
+----------+------------+----------+
| check_no | issue_date | payee |
+----------+------------+----------+
| 0 | 2015-01-01 | 11101-15 |
| 1 | 2015-01-24 | 11101-15 |
| 34561 | 2015-01-24 | Chen Lou |
| 34562 | 2015-01-24 | Shay Ridz|
+----------+------------+----------+
請在這里幫助我的查詢。 將不勝感激。 謝謝
SELECT id.issue_date AS date,
id.check_no AS check_no,
COALESCE( p.payee_name, id.lddap_no ) AS payee
FROM issue_details id
LEFT JOIN payees p ON
id.payee_id = p.payee_id
請參見SQLFiddle演示
只需將INNER JOIN
更改為LEFT JOIN
SELECT issue_details.issue_date AS date,
issue_details.check_no AS check_no,
payees.payee_name AS payee
FROM
issue_details
LEFT JOIN payees ON
issue_details.payee_id = payees.payee_id
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