[英]Getting 404 error with TOMCAT-Jersey Rest
我正在使用JERSEY2.15: -
java類: -
package packages.newJersey;
import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.Produces;
import javax.ws.rs.core.MediaType;
@Path("/rest")
public class SimpleWebService {
private static String versions = "4.1";
@GET
@Produces(MediaType.TEXT_HTML)
public String simpleMessage() {
return "<p>This is a simple REST</p>";
}
@Path("/version")
@GET
@Produces(MediaType.TEXT_HTML)
public String version() {
return "<p>Version Number:</p> " + versions;
}
}
web.xml中: -
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
id="WebApp_ID" version="3.0">
<display-name>LatestJersey</display-name>
<servlet>
<servlet-name>Jersey REST Service</servlet-name>
<servlet-class>org.glassfish.jersey.servlet.ServletContainer</servlet-class>
<init-param>
<param-name>jersey.config.server.provider.package</param-name>
<param-value>packages.newJersey</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>Jersey REST Service</servlet-name>
<url-pattern>/hello/*</url-pattern>
</servlet-mapping>
</web-app>
即使我使用顯示名稱: - LatestJersey
默認情況下tomcat正在打開: - http:// localhost:8080 / RESTFULServiceWithLatestJersey /
當我點擊: - http:// localhost:8080 / RESTFULServiceWithLatestJersey / hello / rest
我得到404錯誤
有人可以幫我嗎?
除此之外,一切看起來都不錯
jersey.config.server.provider.package
它應該是
jersey.config.server.provider.packages
你錯過了s
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.