[英]mysql select all unique rows in one column and all max rows in another column by datetime
我需要為每個table_id
獲取最新的(按date_time) unique player_id
表:
buyin_id player_id table_id date_time
---------|-----------|----------|--------------------|
1 | 10 | 21 | 2015-01-26 00:00:01
2 | 11 | 21 | 2015-01-26 00:00:02
3 | 12 | 21 | 2015-01-26 00:00:03
4 | 10 | 21 | 2015-01-26 00:00:04
5 | 11 | 21 | 2015-01-26 00:00:05
6 | 12 | 22 | 2015-01-26 00:00:06
7 | 13 | 22 | 2015-01-26 00:00:07
8 | 13 | 22 | 2015-01-26 00:00:08
所需結果:
buyin_id player_id table_id date_time
---------|-----------|----------|--------------------|
3 | 12 | 21 | 2015-01-26 00:00:03
4 | 10 | 21 | 2015-01-26 00:00:04
5 | 11 | 21 | 2015-01-26 00:00:05
6 | 12 | 22 | 2015-01-26 00:00:06
8 | 13 | 22 | 2015-01-26 00:00:08
我嘗試過這樣的事情,每個table_id只返回1行而不是1行
SELECT pb.buyin_id, pb.player_id, pb.buyin, pb.cashout, pb.cashout_error, pb.date_time
FROM poker_buyin AS pb
INNER JOIN (SELECT player_id, MAX(date_time) AS MaxDateTime
FROM poker_buyin GROUP BY player_id) groupedpb
ON pb.player_id = groupedpb.player_id
AND pb.date_time = groupedpb.MaxDateTime
WHERE pb.player_id = '$player_id'";
您提到的查詢將查找每個玩家ID的最新記錄。 然后,您對其進行過濾以找到一名球員,那么您將獲得一行。
如果要查找每個球員和桌子的最新記錄,則內部查詢需要這樣:
SELECT MAX(buyin_id) buyin_id
FROM poker_buyin
GROUP BY player_id, table_id
這將從表中獲取代表最新播放器/表組合的行ID。
然后使用它從表中提取記錄,例如( http://sqlfiddle.com/#!2/be68b7/2/0 )
SELECT whatever_columns
FROM poker_buyin
WHERE buyin_id IN
(
SELECT MAX(buyin_id) buyin_id
FROM poker_buyin
GROUP BY player_id, table_id
)
WHERE player_id = '$player_id'
ORDER BY player_id, table_id
該查詢中有一個小技巧:buyin_id值不斷上升,因此這是為每個組合選擇最新記錄的好方法。
如果在結果列中不需要buyin_id
,則很簡單:
SELECT DISTINCT player_id, table_id, max(date_time) as dt
FROM `poker_buyin `
GROUP BY player_id, table_id
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