[英]Yii2 REST Example Returns Errant <?PHP Tag
按照此快速入門指南,我已經建立了一個簡單的Yii2應用程序。 它是如此的通用,其中沒有多余的代碼。 但是由於某種原因,我的CURL請求返回了一個額外的<?PHP
標記,這一切都弄糟了。
我的請求:
curl -i -H "Accept:application/json" "http://backend/users"
響應:
HTTP/1.1 200 OK
Date: Wed, 28 Jan 2015 15:55:14 GMT
Server: Apache/2.2.27 (Unix) mod_ssl/2.2.27 OpenSSL/1.0.1j DAV/2 PHP/5.5.16
X-Powered-By: PHP/5.5.16
X-Pagination-Total-Count: 1
X-Pagination-Page-Count: 1
X-Pagination-Current-Page: 1
X-Pagination-Per-Page: 20
Link: <http://backend/users?page=1>; rel=self
Content-Length: 178
Content-Type: application/json; charset=UTF-8
<?php[{"id":1,"email":"chris@email.com","password":"","name":null,"address":null,"address2":null,"city":null,"state":null,"zip":null,"date_created":null,"date_updated":null}]
TL; DR
我的main.php
配置文件如下所示:
<?php
$params = array_merge(
require(__DIR__ . '/../../common/config/params.php'),
require(__DIR__ . '/../../common/config/params-local.php'),
require(__DIR__ . '/params.php'),
require(__DIR__ . '/params-local.php')
);
return [
'id' => 'app-backend',
'basePath' => dirname(__DIR__),
'controllerNamespace' => 'api\controllers',
'bootstrap' => ['log'],
'modules' => [],
'components' => [
'user' => [
'identityClass' => 'common\models\User',
'enableAutoLogin' => true,
],
'urlManager' => [
'enablePrettyUrl' => true,
'enableStrictParsing' => true,
'showScriptName' => false,
'rules' => [
['class' => 'yii\rest\UrlRule', 'controller' => 'user'],
],
],
'request' => [
'parsers' => [
'application/json' => 'yii\web\JsonParser',
]
]
],
'params' => $params,
];
我的UserController.php
文件如下所示:
<?php
namespace backend\controllers;
use yii\rest\ActiveController;
class UserController extends ActiveController
{
public $modelClass = 'common\models\User';
}
我的User.php
模型文件如下所示:
<?php
namespace common\models;
use Yii;
/**
* This is the model class for table "users".
*
* @property integer $id
* @property string $email
* @property string $password
* @property string $name
* @property string $address
* @property string $address2
* @property string $city
* @property string $state
* @property string $zip
* @property string $date_created
* @property string $date_updated
*/
class User extends \yii\db\ActiveRecord
{
/**
* @inheritdoc
*/
public static function tableName()
{
return 'users';
}
/**
* @inheritdoc
*/
public function rules()
{
return [
[['date_created', 'date_updated'], 'safe'],
[['email', 'password'], 'string', 'max' => 255],
[['name', 'address', 'address2'], 'string', 'max' => 100],
[['city'], 'string', 'max' => 50],
[['state'], 'string', 'max' => 2],
[['zip'], 'string', 'max' => 10]
];
}
/**
* @inheritdoc
*/
public function attributeLabels()
{
return [
'id' => 'ID',
'email' => 'Email',
'password' => 'Password',
'name' => 'Name',
'address' => 'Address',
'address2' => 'Address2',
'city' => 'City',
'state' => 'State',
'zip' => 'Zip',
'date_created' => 'Date Created',
'date_updated' => 'Date Updated',
];
}
}
抱歉打擾大家...結果在我的config / bootstrap.php文件中,我的IDE在打開PHP標記后修剪了空格,所以我使用的是“ <?php”而不是“ <?php”,它以字符串形式返回,而不是解析為PHP
我繼續在您的項目文件夾中搜索<php
。
$ grep -r '<php' /path/to/app
如果這樣做沒有幫助,您可以嘗試修改index.php文件以查找將標頭發送到的位置 ,但是如果框架在輸出開始之前發送標頭,則此操作將無效:
if (headers_sent($filename, $linenum)) {
echo "Headers sent in $filename on line $linenum";
}
在非常迅速地遵循他們的指南之后,我能夠做到這一點:
$ curl -i -H "Accept:application/json" "http://localhost/users"
HTTP/1.1 200 OK
Date: Wed, 28 Jan 2015 19:47:03 GMT
Server: Apache
X-Powered-By: PHP/5.5.14
X-Pagination-Total-Count: 1
X-Pagination-Page-Count: 1
X-Pagination-Current-Page: 1
X-Pagination-Per-Page: 20
Link: <http://localhost/users?page=1>; rel=self
Content-Length: 94
Content-Type: application/json; charset=UTF-8
[{"id":1,"created":"2015-01-28 00:00:00","modified":"2015-01-28 00:00:00","name":"Test User"}]
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