在Eclipse中創建Web服務

Question

我正在使用Eclipse Luna，tomcat 7和axis 1.6。 我正在為Spring MVC控制器創建Web服務。 這是我的代碼

 package com.hp.hpl.ress.phoenix.web;
    import com.hp.hpl.ress.phoenix.service.*;
    import com.hp.hpl.ress.phoenix.domain.*;
    import com.hp.hpl.ress.phoenix.flex.service.HomeViewService;
    import com.hp.hpl.ress.phoenix.flex.service.NotificationFacade;
    import com.hp.hpl.ress.phoenix.flex.vo.UserVO;
    import java.util.Calendar;
    import java.util.Date;
    import java.util.GregorianCalendar;
    import java.util.List;
    import java.util.TimeZone;
    import org.apache.log4j.Logger;
    import org.springframework.beans.factory.annotation.Autowired;
    import org.springframework.stereotype.Controller;
    import org.springframework.web.bind.annotation.RequestMapping;
    import org.springframework.web.bind.annotation.RequestParam;
    import org.springframework.web.servlet.ModelAndView;

    @Controller
    public class PhoenixController {
    protected final Logger logger = Logger.getLogger(getClass().getName());
    @Autowired
    private InstallationService installationService;
    @Autowired
    private HomeViewService homeViewService;
    @RequestMapping("/home.htm")
    public ModelAndView showHomePage() {
    List<Installation> allInstallations =    

    installationService.getAllInstallations();
    ModelAndView mav = new ModelAndView("home");
    mav.addObject("pageName", "Home Page");
    mav.addObject("installations", allInstallations);
    return mav;
    }
    @RequestMapping("/viewInstallation.htm")
    public ModelAndView viewInstallation(@RequestParam("installationId") String 

    installationId) {
    logger.debug("Started to render installation view: " + new Date());
    Installation installation =  

    installationService.getInstallation(Integer.parseInt(installationId));
    ModelAndView mav = new ModelAndView("viewInstallationDetail");
    mav.addObject("pageName", "Installation detail");
    mav.addObject("installation", installation);
    logger.debug("Finished rendering installation view: " + new Date());
    return mav;
    }

    @RequestMapping("/viewZone.htm")
    public ModelAndView viewZone(@RequestParam("zoneId") String zoneId) {
    logger.debug("Started to render zone view: " + new Date());
    Zone zone = installationService.getZone(Integer.parseInt(zoneId));
    ModelAndView mav = new ModelAndView("viewZoneDetail");
    mav.addObject("pageName", "Zone detail");
    mav.addObject("zone", zone);
    logger.debug("Finished rendering zone view: " + new Date());
    return mav;
    }

    @RequestMapping("/viewSensor.htm")
    public ModelAndView viewSensor(@RequestParam("sensorId") String sensorId) {
    logger.debug("Started to render sensor view: " + new Date());
    Sensor sensor = installationService.getSensor(Integer.parseInt(sensorId));
    Calendar start =  

    Calendar.getInstance(TimeZone.getTimeZone(sensor.getTimeZone()));
    start.set(Calendar.HOUR_OF_DAY, 0);
    start.set(Calendar.MINUTE, 0);
    start.set(Calendar.SECOND, 0);
    start.set(Calendar.MILLISECOND, 0);
    Calendar end = (GregorianCalendar)start.clone();
    end.add(Calendar.DATE, 1);
    List<SensorReading> readings = 

    installationService.getRangeOfReadings(sensor, start, end);

    ModelAndView mav = new ModelAndView("viewSensorDetail");
    mav.addObject("pageName", "Installation details");
    mav.addObject("sensor", sensor);
    mav.addObject("readings", readings);
    logger.debug("Finished rendering sensor view: " + new Date());
    return mav;
    }


    @RequestMapping("/homeSummary.htm")
    public ModelAndView homeSummary() {
    ModelAndView mav = new ModelAndView("viewHomeSummary");
        //yyyy/MM/dd HH:mm

    UserVO userSummary = homeViewService.getUserSummary(1, "2010/08/01 00:00",  

    3);
    mav.addObject("UserSummary", userSummary);
    return mav;
    }
    public void setInstallationService(InstallationService installationService)    

    {
        this.installationService = installationService;
    }

    }

當我嘗試使用Eclipse為該控制器創建Web服務時，我收到的選擇必定是WSDL錯誤。 我也在項目構面中添加了軸2，

Answer 1

我遇到了同樣的問題，並且我使用了此解決方案。 通過這種方式將spring控制器用作服務：

@RequestMapping(value = "services/utente/getUtenteByUsername", method = RequestMethod.GET)
    @ResponseBody
    public String getUtenteDaUsername( @RequestParam("username") String username, Model model) {

            utente = utenteBo.findByUsername(username);

            String jsonResult = "";

            if (utente != null) {

                    GsonBuilder builder = new GsonBuilder();
                    Gson gson = builder.create();

                    jsonResult = gson.toJson(utente);

                    return jsonResult;
            } 
            else {
                return null;
            }
        } 

我已經使用json發送響應。 希望可以為您提供幫助。