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MySQL查詢以獲取唯一值的小計

[英]MySQL query to get subtotal of unique values

我有以下數據: +---+----+ |Key|Name| +---+----+ |1 |Tom | +---+----+ |2 |Tom | +---+----+ |3 |Dan | +---+----+ |4 |Dan | +---+----+ |5 |Dan | +---+----+ |6 |Dan | +---+----+ |7 |Ken | +---+----+ |8 |Ken | +---+----+ +---+----+ |Key|Name| +---+----+ |1 |Tom | +---+----+ |2 |Tom | +---+----+ |3 |Dan | +---+----+ |4 |Dan | +---+----+ |5 |Dan | +---+----+ |6 |Dan | +---+----+ |7 |Ken | +---+----+ |8 |Ken | +---+----+

並且需要MySQL查詢來獲取此+---+----+-----------+ |Key|Name| subtotal | +---+----+-----------+ |1 |Tom | 2 | +---+----+-----------+ |2 |Tom | 2 | +---+----+-----------+ |3 |Dan | 4 | +---+----+-----------+ |4 |Dan | 4 | +---+----+-----------+ |5 |Dan | 4 | +---+----+-----------+ |6 |Dan | 4 | +---+----+-----------+ |7 |Ken | 2 | +---+----+-----------+ |8 |Ken | 2 | +---+----+-----------+ +---+----+-----------+ |Key|Name| subtotal | +---+----+-----------+ |1 |Tom | 2 | +---+----+-----------+ |2 |Tom | 2 | +---+----+-----------+ |3 |Dan | 4 | +---+----+-----------+ |4 |Dan | 4 | +---+----+-----------+ |5 |Dan | 4 | +---+----+-----------+ |6 |Dan | 4 | +---+----+-----------+ |7 |Ken | 2 | +---+----+-----------+ |8 |Ken | 2 | +---+----+-----------+ +---+----+-----------+ |Key|Name| subtotal | +---+----+-----------+ |1 |Tom | 2 | +---+----+-----------+ |2 |Tom | 2 | +---+----+-----------+ |3 |Dan | 4 | +---+----+-----------+ |4 |Dan | 4 | +---+----+-----------+ |5 |Dan | 4 | +---+----+-----------+ |6 |Dan | 4 | +---+----+-----------+ |7 |Ken | 2 | +---+----+-----------+ |8 |Ken | 2 | +---+----+-----------+相同的數據,但附加的列顯示“名稱”列中唯一名稱的數量。 我嘗試使用count(1)和group by,但是結果以3個名稱項和總數為准,但是我需要每條記錄以及有關多少記錄與Name列中值相同的其他信息

select t1.id, t1.name, t2.total
from your_table t1
join
(
  select name, count(*) as total
  from your_table
  group by name
) t2 on t1.name = t2.name

嘗試這個

select *, (sum(name)) as total from table
group by name

我認為這可以解決您的問題

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