如何合並兩個清單

Question

我可以用兩種方式編寫追加行。 均未產生預期的結果。 有沒有一種方法可以將其包裝成一行？

選項1：

row.append(x[1] for x in emails if x[0] == row[1]) 

產量：

[['project1', 'email1', <generator object <genexpr> at 0x0227D670>], ['project1', 'email2', <generator object <genexpr> at 0x022EB8A0>]]

選項2：

row.append([x[1] for x in emails if x[0] == row[1]]) 

產量：

[['project1', 'email1', ['john@gmail.com']], ['project1', 'email2', ['bill@gmail.com']]]

所需結果：

[['project1', 'email1', 'john@gmail.com'], ['project1', 'email2', 'bill@gmail.com']]

碼：

emails = [['email1','john@gmail.com'],['email2','bill@gmail.com']]

projects = [['project1', 'email1'], ['project1', 'email2']]

for row in projects:
    row.append(x[1] for x in emails if x[0] == row[1])
print projects

Answer 1

在您現有的代碼中，替換這一行：

row.append(x[1] for x in emails if x[0] == row[1])

附：

row.extend(x[1] for x in emails if x[0] == row[1])

一線解決方案

或者，消除循環並將代碼壓縮成一行：

>>> projects = [  row + [x[1] for x in emails if x[0] == row[1]] for row in projects ]
>>> print projects 
[['project1', 'email1', 'john@gmail.com'], ['project1', 'email2', 'bill@gmail.com']]

Answer 2

emails = [['email1','john@gmail.com'],['email2','bill@gmail.com']]

projects = [['project1', 'email1'], ['project1', 'email2']]
from itertools import chain


print([list(set((chain.from_iterable(ele)))) for ele in zip(emails,projects)])
[['email1', 'john@gmail.com', 'project1'], ['email2', 'project1', 'bill@gmail.com']]

要么：

print([list(set(ele).union(projects[ind])) for ind, ele in enumerate(emails)])

要么：

print([projects[ind] + [ele for ele in sub if ele not in projects[ind]] for ind, sub in enumerate(emails)])

所有不同的版本將適用於多個項目，而不僅僅是檢查單個元素。