使用jQuery和Ajax提交表單
[英]Submit a Form with jQuery and Ajax
問題描述
試圖讓我的注冊頁面使用Ajax和jQuery將數據發布到數據庫中，但難度很大。
我對ajax還是很陌生，甘蔗似乎使我了解如何進行此插入。 非常感謝您提供有關此操作的建議。 我不確定目前所獲得的距離是否還很遙遠。
當我單擊“提交”按鈕時，頁面會刷新，但數據庫沒有更改。
* html代碼
<html>
<head>
<title>Register</title>
<link rel="stylesheet" type="text/css" href="../css/stylesheet.css">
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js"></script>
<script type="text/javascript" src="../js/validation.js"></script>
<script type="text/javascript" src="../js/registerpost.js"></script>
</head>
<body>
<div id="container">
<div id="mainContent")>
<form class="basic-grey" method="post">
<h1>Registration Form<span>Please complete all fields.</span></h1>
<p>
<label><span>First Name:</span>
<input name="firstname" id="firstname" type="text" size="40" maxlength="40" placeholder="First Name" required/>
</label>
<label><span>Surname:</span>
<input name="lastname" id="lastname" type="text" size="40" maxlength="40" placeholder="Surname" required/>
</label>
<label><span>Username:</span>
<input name="username" id="username" oninput="checkUsername();" type="text" size="40" maxlength="40" placeholder="Username" required/>
</label>
<label><span>Email:</span>
<input name="email" id="email" oninput="checkEmail();" type="email" size="40" maxlength="40" placeholder="Email" required/>
</label>
<label><span>Password:</span>
<input name="password1" id="password1" type="password" size="40" maxlength="40" placeholder="********" required/>
</label>
<label><span>Confirm Password:</span>
<input name="password2" id="password2" oninput="checkPassword();" type="password" size="40" placeholder="********" required/>
</label>
</p>
<div align="center"><span align = "center" id="user-result"></span><br><br><br>
</div>
<div align="center">
<span> </span><input type="submit" class="button" id="submit_btn" value="Submit" />
</div>
</form>
</form>
</div>
</div>
</body>
</html>
PHP代碼
<?php
include 'connection.php';
$hash = password_hash($_POST['password2'], PASSWORD_DEFAULT, ['cost' => 11]);
$sql = "INSERT INTO members(firstname, lastname, username, email, password )
VALUES(:firstname, :lastname, :username, :email, :password )";
$stmt = $db->prepare($sql);
$stmt->bindParam(':firstname', $_POST['firstname'], PDO::PARAM_STR);
$stmt->bindParam(':lastname', $_POST['lastname'], PDO::PARAM_STR);
$stmt->bindParam(':username', $_POST['username'], PDO::PARAM_STR);
$stmt->bindParam(':email', $_POST['email'], PDO::PARAM_STR);
$stmt->bindParam(':password', $hash, PDO::PARAM_STR);
$results->$stmt->execute();
if($results) {
echo 'Welcome new member, and thanks you for registering with the website.';
echo '<br><br>Click <a href="../index.html">here</a> to return to the login page';
} else {
echo 'Did not work.';
}
?>
js代碼
$(document).ready(function() {
$('#submit_btn').click(function(){
var data = {};
data.firstname = $('#firstname').val();
data.lastname = $('#lastname').val();
data.username = $('#username').val();
data.email = $('#email').val();
data.password2 = $('#password2').val();
$.ajax({
type: "POST",
url: "../php/newuser.php",
data: data,
cache: false,
success: function (response) {
}
});
return false;
});
});
任何幫助將不勝感激。
謝謝
2 個解決方案
解決方案1
0 2015-02-05 03:17:52
你可以做這樣的事情。 在此處查看詳細信息： https : //webdevideas.wordpress.com/2013/07/30/n-forms-one-javascript/
$（document）.ready（function（）{
$（“。ajaxform”）。bind（“ submit”，function（e）{
e.preventDefault();
var ajaxurl = $(this).attr("action");
var data = $(this).serialize();
$.post(ajaxurl,data,function(res){
$("#message").html(res.message);
},'json');
}）;
}）;
解決方案2
0 2015-02-05 03:24:23
解決了這是我在PHP文件中犯的一個簡單錯誤。
這個
$results->$stmt->execute();
對此
$results = $stmt->execute();
謝謝大家
jQuery（ajax）提交表格
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