[英]Class PHP methods get and set
我有這個課:
<?php
class Test {
private $_ID;
private $_NAME;
private $_AGE;
public function setID() { $this->_ID++; }
public function getID() { return $this->_ID; }
public function setNAME($element) { $this->_NAME = $element; }
public function getNAME() { return $this->_NAME; }
public function setAGE($element) { $this->_AGE = $element; }
public function getAGE() { return $this->_AGE; }
public function addUser($name, $age) {
Test::setID();
Test::setNAME($name);
Test::setAGE($age);
echo "OK";
}
}
?>
我想創建此類的對象,並使用以下函數addUser分配數據:
$test = new Test();
$test:: addUser("Peter", "12"); but I have errors.
我有這個錯誤:
嚴格標准:非靜態方法Test :: addUser()不應在第13行的/var/www/public/testManu.php中被靜態調用
嚴格標准:非靜態方法Test :: setID()不應在第18行的/var/www/public/class/Test.php中被靜態調用
致命錯誤:第8行的/var/www/public/class/Test.php中不在對象上下文中時使用$ this
我有可變范圍的問題。 有人可以告訴我這是我的問題嗎????
改變這個:
...
public function addUser($name, $age) {
$this->setID();
$this->setNAME($name);
$this->setAGE($age);
echo "OK";
}
...
像Classname::function()
這樣的調用僅對靜態方法有效。 您有一個專用實例,需要使用構造$this->function()
。
因此:
...
$test->addUser("Peter", "12"); but I have errors.
$test = new Test();
$test -> addUser("Peter", "12"); #now no errors
這應該為您工作:
<?php
class Test {
private static $_ID = 1;
private static $_NAME;
private static $_AGE;
public static function setID() { self::$_ID++; }
public static function getID() { return self::$_ID; }
public static function setNAME($element) { self::$_NAME = $element; }
public static function getNAME() { return self::$_NAME; }
public static function setAGE($element) { self::$_AGE = $element; }
public static function getAGE() { return self::$_AGE; }
public static function addUser($name, $age) {
self::setID();
self::setNAME($name);
self::setAGE($age);
echo "OK";
}
}
$test = new Test(); /*You don't need to instantiate the class
because you're calling a static function*/
$test:: addUser("Peter", "12"); but I have errors.
?>
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