[英]Extracting key-value pairs from multiline text in java
考慮以下多行字符串:
This is multiline text that needs to be correctly parsed into key-value pairs, excluding all other information.
Section One:
First key = Value One
Second key = Value Two
Section Two:
Third key = Value Three
Fourth key = Value Four
Fifth key = Value Five
Section Three:
Sixth key = Value Six
Seventh key = Value Seven
Eighth key = Value Eight
換句話說,文本由一個“簡介”(一些短語)組成,然后是多行,每節各有一部分,每個行都有一個“標題”(例如,“ Section One
)和多個鍵值對,並以=
。
鍵可以包含除換行和=
之外的任何字符,並且值可以包含除換行之外的任何字符。
有時,其他不相關的行可能會出現在文本中。
需要一個正則表達式,該matched.find()
將使matched.find()
返回所有鍵值對組,並且僅返回那些鍵值對組,同時跳過簡介和節標題以及任何其他沒有鍵值對的行。
理想情況下,不需要其他文本預處理或后處理。
在此用例中,不能逐行讀取文本並進行相應處理。
像(?:\\r|\\n)(\\s*[^=\\.]+)\\s*=\\s*(.+)
接近,但它們仍然包含更多要求。
有任何想法嗎?
你快到了 。 只需將\\s*
更改為<space>*
因為\\s
也會匹配換行符。
(?:\r|\n) *([^\n=\.]+)(?<=\S) *= *(.+)
如果包含選項卡,則將上面的space*
更改為[ \\t]*
。 (?<=\\S)
正向后看,它斷言匹配必須以非空格字符開頭。
String s = "This is multiline text that needs to be correctly parsed into key-value pairs, excluding all other information.\n" +
"\n" +
" Section One:\n" +
" First key = Value One\n" +
" Second key = Value Two\n" +
"\n" +
" Section Two: \n" +
" Third key = Value Three\n" +
" Fourth key = Value Four\n" +
" Fifth key = Value Five\n" +
"\n" +
" Section Three:\n" +
" Sixth key = Value Six\n" +
" Seventh key = Value Seven\n" +
" Eighth key = Value Eight";
Matcher m = Pattern.compile("(?:\\r|\\n)[\\t ]*([^\\n=\\.]+)(?<=\\S)[\\t ]*=[\\t ]*(.+)").matcher(s);
while(m.find())
{
System.out.println("Key : "+m.group(1) + " => Value : " + m.group(2));
}
輸出:
Key : First key => Value : Value One
Key : Second key => Value : Value Two
Key : Third key => Value : Value Three
Key : Fourth key => Value : Value Four
Key : Fifth key => Value : Value Five
Key : Sixth key => Value : Value Six
Key : Seventh key => Value : Value Seven
Key : Eighth key => Value : Value Eight
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