Codeigniter db選擇哪里作為數組

Question

我有此代碼，我需要使用它來從數據庫中獲取結果，我正在使用codeigniter。 這就是查詢的樣子，

        $this->db->select('*');
        $this->db->where('broadcast_id', $bid);
        $query = $this->db->get('ih_noticeboard');
        $result = $query->result();
        if($query->num_rows() < 1){
            $data = "no feed ";
        }else{
            $data = $result;
        }

where子句中的$bid從此代碼獲取，

    $this->db->select('broadcast_id');
    $this->db->where('broadcast_subscribers', $id);
    $query = $this->db->get('ih_broadcastors    ');
    if($query->num_rows() < 1){
        $data = "user not subscribed to any broadcasting";
    }else{
        $ress = $query->result();
        foreach ($ress as $row){
            $bid = $row->broadcast_id;
        }`

現在選擇僅使用一個$ bid，如何將$ bid用作數組？

Answer 1

這很簡單。 只需使用$ this-> db-> where_in（'broadcast_id'，$ bid）;

相反，如果$ this-> db-> where（'broadcast_id'，$ bid）;

https://ellislab.com/codeigniter/user-guide/database/active_record.html#select

Answer 2

有一個查詢來獲取提要更好嗎？

$this->db->select("ih_noticeboard.*");
$this->db->from("ih_noticeboard");
$this->db->join("ih_broadcastors", "ih_noticeboard.broadcast_id = ih_broadcasters.broadcast_id");
$this->db->where("ih_broadcastors.broadcast_subscribers", $id);
$result->db->get()->result();

Answer 3

假設您要在表格中選擇

例如，name ='jane'和broadcast_id = 2

        $bid=array(
           'name'=>'jane',
           'broadcast_id'=>'2'
                  ) 

        $this->db->where($bid);
        $this->db->from($table_name);
        $query = $this->db->get()->result_array();
        return $query;

請注意，必須將$ bid as數組格式化為適合要查詢的下一個數據庫表的格式。 您可以使用foreach循環執行此操作

   foreach ($ress as $row){
        $bid = array(
             'name'=>$row['name'],
             'broadcast_id'=>$row['id']
         );
    }